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Suppose you are testing Ho: p= .29 versus Ha: p.29. A random sample of 740 items shows that 207 have this characteristic. With a.05 probability of committing a Type I error, test the hypothesis. For the p-value method, what is the probability of the observ z value for this problem? If you had used the critical value method, what would the two critical values be? How do the sample results compare with the critical values? Appendix A Statistical Tables (Round the value of z to 2 decimal places, e.g. 15.75. Round the value of p to 4 decimal places, e.g. 15.7595. Round the critical values and t decimal places, e.g. 15.754. Enter negative amounts using either a negative sign preceding the number e.g. -45 or parentheses e.g. (45).) The value of the test statistic is z = The p-value is Lower critical value: Upper critical value: Since p = .when it is compared with a/2, we is not outside critical values in tails, the decision is to

Suppose you are testing Ho: p= .29 versus Ha: p.29. A random sample of 740 items shows that 207 have this characteristic. With a.05 probability of committing a Type I error, test the hypothesis. For the p-value method, what is the probability of the observ z value for this problem? If you had used the critical value method, what would the two critical values be? How do the sample results compare with the critical values? Appendix A Statistical Tables (Round the value of z to 2 decimal places, e.g. 15.75. Round the value of p to 4 decimal places, e.g. 15.7595. Round the critical values and t decimal places, e.g. 15.754. Enter negative amounts using either a negative sign preceding the number e.g. -45 or parentheses e.g. (45).) The value of the test statistic is z = The p-value is Lower critical value: Upper critical value: Since p = .when it is compared with a/2, we is not outside critical values in tails, the decision is to

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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can you help me answer this but from lower critical value on wards the first 3 blanks are already answered 

Suppose you are testing Ho: p = .29 versus Ha:p ‡ .29. A random sample of 740 items shows that 207 have this characteristic. With a .05 probability of committing a Type I error, test the hypothesis. For the p-value method, what is the probability of the observed z value for this problem? If you had used the critical value method, what would the two critical values be? How do the sample results compare with the critical values? Appendix A Statistical Tables (Round the value of z to 2 decimal places, e.g. 15.75. Round the value of p to 4 decimal places, e.g. 15.7595. Round the critical values and p to 3 decimal places, e.g. 15.754. Enter negative amounts using either a negative sign preceding the number e.g. -45 or parentheses e.g. (45).) The value of the test statistic is z = The p-value is Lower critical value: Upper critical value: Since p = .when it is compared with a/2, we is not outside critical values in tails, the decision is to
Transcribed Image Text:Suppose you are testing Ho: p = .29 versus Ha:p ‡ .29. A random sample of 740 items shows that 207 have this characteristic. With a .05 probability of committing a Type I error, test the hypothesis. For the p-value method, what is the probability of the observed z value for this problem? If you had used the critical value method, what would the two critical values be? How do the sample results compare with the critical values? Appendix A Statistical Tables (Round the value of z to 2 decimal places, e.g. 15.75. Round the value of p to 4 decimal places, e.g. 15.7595. Round the critical values and p to 3 decimal places, e.g. 15.754. Enter negative amounts using either a negative sign preceding the number e.g. -45 or parentheses e.g. (45).) The value of the test statistic is z = The p-value is Lower critical value: Upper critical value: Since p = .when it is compared with a/2, we is not outside critical values in tails, the decision is to
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