Apply Variation of Parameters to find the general solution. e* у"- 2у'+ у 3 1+x?

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
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**Applying Variation of Parameters to Solve a Differential Equation**

To find the general solution of the differential equation, use the method of Variation of Parameters:

\[ y'' - 2y' + y = \frac{e^x}{1 + x^2} \]

This method is used for solving non-homogeneous linear differential equations. The equation given is second-order and linear, making it suitable for this approach. The solution involves finding a particular solution to the non-homogeneous equation and adding it to the general solution of the corresponding homogeneous equation.
Transcribed Image Text:**Applying Variation of Parameters to Solve a Differential Equation** To find the general solution of the differential equation, use the method of Variation of Parameters: \[ y'' - 2y' + y = \frac{e^x}{1 + x^2} \] This method is used for solving non-homogeneous linear differential equations. The equation given is second-order and linear, making it suitable for this approach. The solution involves finding a particular solution to the non-homogeneous equation and adding it to the general solution of the corresponding homogeneous equation.
Expert Solution
Step 1

Given

y''-2y'+y=ex1+x2

Step 2

Now

y''-2y'+y=ex1+x2The auxiliary equation ism2-2m+1=0m2-m-m+1=0mm-1-1m-1=0m-1m-1=0m=1,1Therefore the complementary function C.F.=Aex+Bxex     .....1NowWy1,y2=y1y2y1'y2'From equation 1, y1=ex ,y2=xexand y1'=ex ,y2'=x+1exThenWy1,y2=exxexexx+1exWy1,y2=x+1e2x-xe2xWy1,y2=e2x

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