Suppose you are testing H_0 : \mu =H0:μ= 107 against H_a : \mu
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A: Given that Sample size n =15 Sample mean =5.36 Population standard deviation =1.93
Q: Suppose a variable is Normally distributed with μ=345 and \sigma σ=30. What proportion of the data…
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Suppose you are testing H_0 : \mu =H0:μ= 107 against H_a : \mu <Ha:μ< 107. From an SRS of 83 individuals, you compute \bar x =xˉ= 112 and s =s= 4.8.
What is the value of the tt-test statistic in this test? Round your answer to three decimal places.
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- You are performing a left-tailed test with test statistic z=−2.945z=-2.945, find the p-value accurate to 4 decimal places. p-value =We found no difference on the reported self-esteem level between female participants (M=5.39, SD = .83) and male participants (M = 5.50, SD = .78), t (152) = -.86, p=.393. What was the design of this study? Between-subjects/Within-subjects (Please choose) What was the DV (variable of interest)? How many participants were included in the analysis? In average, what was male participants’ reported self-esteem level in this study? Was the null hypothesis rejected? Yes/No (Please choose)Calculate the quartiles, and inter quartile range Determine if there are any unexpected values
- PLEASE DO IN Excel A clinical trial is run to assess the effects of different forms of regular exercise on HDL levels in persons between the ages of 18 and 29. Participants in the study are randomly assigned to one of three exercise groups - Weight training, Aerobic exercise or Stretching/Yoga – and instructed to follow the program for 8 weeks. Their HDL levels are measured after 8 weeks and are summarized below. Is there a significant difference in mean HDL levels among the exercise groups? Run the test at a 5% level of significance. HINT: SSerror = 7286.5. Exercise Group N Mean Std Dev Weight Training 20 49.7 10.2 Aerobic Exercise 20 43.1 11.1 Stretching/Yoga 20 57 12.5 Step 1. Set up hypotheses and determine level of significance. Ho: H1: alpha: Step 2. Select the appropriate test statistic and give its formula.…The FDA regulates that fish that are consumed should contain no more than 1.0 mg/kg of mercury. In Florida, bass fish were collected in 24 different lakes to measure the amount of mercury in the fish ('Multi- disciplinary niser activity, 2013). The data for the average amount of mercury in the fish from each lake is in table below. Average mercury level in a lake 0.71 0.15 0.17 0.63 0.43 1.08 0.27 0.5 0.19 1.20 0.94 0.87 0.48 0.44 0.98 0.59 0.28 0.49 1.16 0.25 1.23 0.77 0.73 0.65 For the data shown above, find the following. Round values 3 decimal place (s). Select the correct units for each statistic.Unfortunately, arsenic occurs naturally in some ground water. A mean arsenic level of µ = 8 parts per billion (ppb) is considered safe for agricultural use. A well in Los Banos is used to water cotton crops. This well is tested on a regular basis for arsenic. A random sample of 37 tests gave a sample mean of - = 7.3 ppb arsenic. It is known that o = information indicate that the mean level of arsenic in this well is less than 8 ppb? Use the classical 1.9ppb for this type of data. Does this approach. Use a = 0.01 What is the criterion (step 3) for this problem? 2.33 or more 1.645 or more -2.33 or less -1.645 or less
- myopenmath.com/assess2/?čid=97456&aid%36979687#/skip/5 Stephen Stigler determined in 1977 that the speed of light is 299,710.5 km/sec. Some measurements of the speed of light are given in the table. Is there evidence to show that the data value of the speed of light? Test at the 1% level. different from Stigler's Speed of Light Measurements in (km/sec) 300004 299740 299824 299706 299793 299765 299831 299539 299814 299737 299593 299689 299654 299836 299880 299763 299712 299700 299793 299568 299704 299796 299651 299548 299737 299636 299788 State the hypotheses. Find the point estimate. Round to three decimal places. Find the test statistic. Round to three decimal places. t = Find the p-value. Round to four decimal places. p-value - State your decision. O Since the p-value is less than 0.01, fail to reject Ho. O Since the p-value is greater than 0.01, reject Ho- O Since the p-value is greater than 0.01, fail to reject Ho. O Since the p-value is less than 0.01, reject Ho. Interpret the…I wanted to test if the mean Exam 3 score in this course was different than the mean Exam 2 score. To conduct this test I used the 30 students in my course last semester as my sample. I first calculated the difference in scores between Exam 2 and Exam 3 ("Exam 2 score - Exam 3 score"). The sample mean of these differences is 2.0 and the sample standard deviation of the differences is 3.0. What is your decision for this test? Group of answer choices 1. Reject the null hypothesis 2. Retain the null hypothesisThe Urban Development Index (UDI) is a standardized measure used to observe and measure the mental development of infants over time. It is approximately normal with mean 90 and standard deviation 12. What proportion of children has UDI of at least 80? Find the MDI score that corresponds to 99th What proportion of children will have an UDI score of at most 110? What percentage of infants will have an UDI score between 80 and 120?
- High density lipoprotein (HDL) in healthy males follows a normal distribution with a mean of 50 and a standard deviation of 8. What proportion of healthy males has HDL exceeding 60?The NTSB wants to estimate the difference between the average stopping distance for a car traveling 40 MPH on wet versus dry pavement. Ten vehicles were used for the study where each vehicle was driven at 40 MPH and came to a sudden stop on both wet pavement and dry pavement. The stopping distance was measured (feet) for each pavement condition and the data is shown below followed by Minitab output with the CI. Estimation for Paired Difference Mean StDev SE Mean 95% CI forμ_difference 34.700 2.452 0.775 (32.946, 36.454) b. What assumption is needed for this CI to be valid?You are conducting a study to see if the accuracy rate for fingerprint identification is significantly less than 0.24. Thus you are performing a left-tailed test. Your sample data produce the test statistic z=−2.287z=-2.287. Find the p-value accurate to 4 decimal places.p-value =
