Suppose you are interested in the rate of autism among current school-aged children in Utah. You collect a sample of 400 children between the ages of 5 and 18 and find that two have had a previous diagnosis of an autism disorder. You plan to calculate a 95% confidence interval estimator of the proportion of school-aged children in Utah who have ever had a diagnosis of an autism disorder. Which of the following is the most likely reason you would use a Wilson estimator to calculate the confidence interval estimator? A confidence interval estimator based on the Wilson estimator does not use the normal distribution. It is possible that if even the actual proportion in Utah is 1%, your sample may only have very few children who have had a previous diagnosis of an autism disorder. It is an easier way to calculate the confidence interval estimator. It is uncomfortable to define having been diagnosed with autism as a success. Let p be the proportion of school-aged children in Utah who have ever had a diagnosis of an autism disorder. Using the Wilson estimate, the 95% confidence interval estimate of p is0.0099 ± . (Hint: For a 95% confidence interval estimate, use zα/2zα/2 = 1.96.)
Suppose you are interested in the rate of autism among current school-aged children in Utah. You collect a sample of 400 children between the ages of 5 and 18 and find that two have had a previous diagnosis of an autism disorder. You plan to calculate a 95% confidence interval estimator of the proportion of school-aged children in Utah who have ever had a diagnosis of an autism disorder. Which of the following is the most likely reason you would use a Wilson estimator to calculate the confidence interval estimator? A confidence interval estimator based on the Wilson estimator does not use the normal distribution. It is possible that if even the actual proportion in Utah is 1%, your sample may only have very few children who have had a previous diagnosis of an autism disorder. It is an easier way to calculate the confidence interval estimator. It is uncomfortable to define having been diagnosed with autism as a success. Let p be the proportion of school-aged children in Utah who have ever had a diagnosis of an autism disorder. Using the Wilson estimate, the 95% confidence interval estimate of p is0.0099 ± . (Hint: For a 95% confidence interval estimate, use zα/2zα/2 = 1.96.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Suppose you are interested in the rate of autism among current school-aged children in Utah. You collect a sample of 400 children between the ages of 5 and 18 and find that two have had a previous diagnosis of an autism disorder. You plan to calculate a 95% confidence interval estimator of the proportion of school-aged children in Utah who have ever had a diagnosis of an autism disorder.
Which of the following is the most likely reason you would use a Wilson estimator to calculate the confidence interval estimator?
A confidence interval estimator based on the Wilson estimator does not use the normal distribution .
It is possible that if even the actual proportion in Utah is 1%, your sample may only have very few children who have had a previous diagnosis of an autism disorder.
It is an easier way to calculate the confidence interval estimator.
It is uncomfortable to define having been diagnosed with autism as a success.
Let p be the proportion of school-aged children in Utah who have ever had a diagnosis of an autism disorder. Using the Wilson estimate, the 95% confidence interval estimate of p is0.0099 ± . (Hint: For a 95% confidence interval estimate, use zα/2zα/2 = 1.96.)
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