If n = 370 and p=0.31p, construct a 90% confidence interval. This should be rounded to three decimal plac
Q: In a sample of 310 adults, 205 had children. Construct a 99% confidence interval for the true…
A: Given data, n=310 x=205 p=x/n=205/310=0.661 z-value at 99% confidence is Zc=2.576
Q: An environmentalist wants to find out the fraction of oil tankers that have spills each month. Step…
A: Consider that p is the true population proportion of the judges ship with no spills. Then the point…
Q: Express the confidence interval (68 % , 79.6 % ) in the form of p + ME.
A: The mid-point of the confidence interval gives the value of p-cap.
Q: Construct a 95% confidence interval for the proportion of adults from the East who say traffic…
A: n = 400 p = 0.34
Q: In a sample of 350 adults, 277 had children. Construct a 99% confidence interval for the true…
A: The sample size, i.e., the sampled number of adults, n=350.The sampled number of adults with…
Q: If X=70, σ=14, and n=61, construct a 99% confidence interval estimate of the population mean,…
A:
Q: a 95% confidence interval estimate for population mean is determined to be 75.38 to 86.52. if the…
A: We have to find the confidence level is reduced to 90%, the confidence interval will....
Q: Express the confidence interval (48.7 % , 58.5 % ) in the form of p ± E.
A: Given information confidence interval (48.7%,58.5%)
Q: Out of 240 sample students surveyed, 187 students are planning to take classes during the…
A: We have given that the sample size n=240 and favourable cases X=187. Sample proportion p^ = X/n.
Q: Express the confidence interval mathematically. Do not round answers.
A: Let be the population mean number of hours adults work each week.Given that,Sample size Sample mean…
Q: A national organization conducted a survey of 1300 American adults and asked how many hours they…
A: sample mean()=40.5Margin of error(E)=0.8
Q: Part A: Make a 90% confidence interval for given that you have a sample of size 49 which produced a…
A: Given,margin of error(E)=0.2standard error(σ)=3.2α=1-0.90=0.10α2=0.05Z0.05=1.645 (from Z-table)
Q: If n=10, 7(x-bar)=49, and s-2, find the margin of error at a 80% confidence level Give your answer…
A:
Q: If n=41n=41, ¯xx¯=36, and s=9s=9, find the margin of error for a 80% confidence level.
A: Answer - Given, Sample size n = 41, x = 36 and s = 9 80% confidence interval…
Q: A researcher wanted to check whether the percentage of Canadian adults with obesity has decreased in…
A: Number of Canadian adults in 2005= 75 Number of Canadian adults in 2009 = 120 significance level =…
Q: Everything else being equal, a population with a higher mean yields a confidence interval that is…
A: As the formula for confidence interval is: CI=X±Zsn Where: X = Mean of the data's Z = Z-value…
Q: In a sample of 500 adults, 340 had children. Construct a 99% confidence interval for the true…
A: Proportion is almost similar to the concept of probability. Proportion is a fraction of a population…
Q: If n=17, (x-bar)-45, and o =12, construct a confidence interval at a 80% confidence level. Assume…
A: Given X-bar=45 S=12 n=17
Q: he lower end of the 95% confidence interval is Question Blank 1 of 2and the higher end of the 95%…
A: n=8 Sample sizex= 9.8 Sample mean s= 0.4 Sample standard deviation
Q: In a sample of 290 adults, 191 had children. Construct a 95% confidence interval for the true…
A: 0.604 < p < 0.713 Explanation:Approach to solving the question:To construct a 95% confidence…
Q: In a sample of 240 adults, 180 had children. Construct a 95% confidence interval for the true…
A:
Q: If α = 0.05, then what is the confidence level?
A: Given: α = 0.05 we know that, Confidence level+ α = 1
Q: In a sample of 360 adults, 245 had children. Construct a 99% confidence interval for the true…
A:
Q: In a random sample of 500 Americans, 50% indicated that they have a cat for a pet. Estimate with 95%…
A: Given information
Q: In a sample of 350 adults, 277 had children. Construct a 99% confidence interval for the true…
A: Sample size, Number of adults having children, Confidence level is .
Q: In a clinical trial of a certain drug, 30 subjects experience headaches among the 220 subjects…
A: Step 1: State the given: number of favorable cases, x = 30sample size, n = 220confidence level =…
Q: Suppose you calculate a 95% confidence interval for a proportion to to be: 0.39 to 0.78. Determine…
A: Given, Lower bound = 0.39 Upper bound = 0.78 Here, we use to determine the margin of error.
Q: в, — 42, s — 8.8, SS,, — 64, п — 19 90% : < B1< 99% : < B1 S
A: Given beta cap1 =42, s=8.8, SS xx =64 , n = 19
Q: In a sample of 400 adults, 220 had children. Construct a 90% confidence interval for population…
A:
Q: Suppose a sample of 779 tenth graders is drawn. Of the students sampled, 202 read at or below the…
A: In question, Given that a sample of 779 tenth graders is drawn. Of the students sampled, 202 read at…
Q: A sample of 1100 observations taken from a population produced a sample proportion of 0.36 . Make a…
A: Given information Sample proportion = 0.36 Sample size (n) = 1100
Q: In a survey of 2092 adults in a recent year, 748 made a New Year's resolution to eat healthier.…
A: Given data n=2092 x=748
Q: If n=260 and X = 208, construct a 95% confidence interval. Give your answers to three decimals __…
A: Solution: From the given information, X=208, n=260 and the confidence level is 0.95. The sample…
Q: What would answer be at 99% confidence interval?
A: We have given that, Sample proportion (p̂) = 64% = 0.64 and sample size (n) = 550 Then, We will…
Q: Each man in a random sample of n = 16 men between 30 and 39 years old is asked to do as many sit-ups…
A: We have given that, Sample mean (x̄) = 24.2, standard deviation (s) = 8 and sample size (n) = 16…
Q: Of 102 randomly selected adults, 42 were found to have high blood pressure. A 90% confidence…
A:
Q: Express the confidence interval (70.4%,80.4%) in the form of ˆp±ME
A: It is given that the confidence interval is (70.4%, 80.4%).
If n = 370 and p=0.31p, construct a 90% confidence interval. This should be rounded to three decimal places.
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 3 images
- In a sample of 470 adults, 306 had children. Construct a 99% confidence interval for the true population proportion of adults with children.Give your answers as decimals, to three places < p <A 90% confidence interval for the difference between the proportion of college students who use flash cards for studying and high school students who use flash cards for studying is (0.13, 0.23). Then the Error is +5%. True FalseIn a sample of 460 adults, 281 had children. Construct a 90% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three places < p <
- Suppose you compute a confidence interval with a sample size of 25. What will happen to the confidence interval if the sample size increases to 37? The confidence interval will widen. The confidence interval will narrow. The width of the confidence interval will stay the same.If n = 20, the sample mean = 250, SD = 15, SEM = 3.354, what is the confidence interval (using 95% confidence level). What percent confidence do you have that the population mean is between what two valuesIf n = 590 and ˆp = 0.94, construct a 95% confidence interval.Give your answers to three decimals __< p < __
- A survey is taken of 250 students, and a P of 0.45 is found. The same survey is repeated with 1,000 students, and the same value is found. Compare the two 95% confidence intervals. What is the relationship? Is the margin of error for the second one four times smaller? How much smaller is it?The following table gives the average number of hours 5 junior high students were left unsupervised each day and their corresponding overall grade averages. Hours Unsupervised 2 2 4 6 6 Overall Grades 64 73 76 77 86 Show Transcribed Text Step 1 of 5: Calculate the sum of squared errors (SSE). Use the values = 62.2000 and b, 3.2500 for the calculations, Round your answer to three decimal places Table Copy Data Step 2 of 5: Calculate the estimated variance of errors. 2. Round your answer to three decimal places. Show Transcribed Text Step 3 of 5: Calculate the estimated variance of slope. s. Round your answer to three decimal places.A researcher from a national reading program conducted a poll of 650 American adults over the age of 30-years-old and asked how many books they read over the past year. The researcher reported that American adults over the age of 30-years-old read a mean number of 13.5 books. The report included a margin of error of 1.25 books. (Assume 95% confidence was used.) Step 2 of 3 : Express the confidence interval mathematically. Do not round answers.
- In a sample of 360 adults, 266 had children. Construct a 95% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three placesif a 95% confidence intervalgivess 0.20 and 0.27, can we be 95% that the proportion is 22% accurate or not because not all values are within 22%?In a sample of 510 adults, 281 had children. Construct a 95% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three placesRecommended textbooks for youA First Course in Probability (10th Edition)ProbabilityISBN:9780134753119Author:Sheldon RossPublisher:PEARSON
A First Course in Probability (10th Edition)ProbabilityISBN:9780134753119Author:Sheldon RossPublisher:PEARSON