Suppose we wish to use Mathematical Induction to prove that for any integer n >1 6" – 1 is divisible by 5: Hint: First write down what P(1) as if you were planning to prove it. Then write down what P(k+1) says as if you were assuming that P(k) is true. Hint: Do not simplify too much. P(1) says 6' – 1 = If we assume the inductive hypothesis that 6* – 1 = 5q for some integer q >1 , then P(k+1) says -5r for some integer r not necessarily equal to q.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Suppose we wish to use Mathematical Induction to prove that for any integer n >1
6" – 1 is divisible by 5:
Hint: First write down what P(1) as if you were planning to prove it. Then write down what P(k+1) says as if
you were assuming that P(k) is true. Hint: Do not simplify too much.
P(1) says 61 – 1 =
If we assume the inductive hypothesis that 6* – 1 = 5q for some integer q >1, then P(k+1) says
=5r for some integer r not necessarily equal to q.
Transcribed Image Text:Suppose we wish to use Mathematical Induction to prove that for any integer n >1 6" – 1 is divisible by 5: Hint: First write down what P(1) as if you were planning to prove it. Then write down what P(k+1) says as if you were assuming that P(k) is true. Hint: Do not simplify too much. P(1) says 61 – 1 = If we assume the inductive hypothesis that 6* – 1 = 5q for some integer q >1, then P(k+1) says =5r for some integer r not necessarily equal to q.
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