Suppose we want to express the concentration of a 0.396m glucose (CeH;2O6) solution in molarity. There is 0.396 mole of glucose in 1000 g of the solvent. _5. What is the mass of the solution from the molar mass of glucose? A. 1063g _6. What is the volume of the solution in liters? d=m/v B. 1067g C. 1071g D. 1075g A. 1000L B. 0.501L C. 0.926L D. 1075g _7. What is the volume of the solution in liters? d=m/v A. 0.511mol/L B. 0.471mo/L C. 0.459mol/L D. 0.429mol/L

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Suppose we want to express the concentration of a 0.396m glucose (CeH;2O6) solution in
molarity. There is 0.396 mole of glucose in 1000 g of the solvent.
_5. What is the mass of the solution from the molar mass of glucose?
A. 1063g
_6. What is the volume of the solution in liters? d=m/N
B. 1067g
C. 1071g
D. 1075g
C. 0.926L
D. 1075g
A. 1000L
_7. What is the volume of the solution in liters? d=m/v
A. 0.511mol/L
B. 0.501L
B. 0.471mol/L
C. 0.459mol/L
D. 0.429mol/L
Transcribed Image Text:Suppose we want to express the concentration of a 0.396m glucose (CeH;2O6) solution in molarity. There is 0.396 mole of glucose in 1000 g of the solvent. _5. What is the mass of the solution from the molar mass of glucose? A. 1063g _6. What is the volume of the solution in liters? d=m/N B. 1067g C. 1071g D. 1075g C. 0.926L D. 1075g A. 1000L _7. What is the volume of the solution in liters? d=m/v A. 0.511mol/L B. 0.501L B. 0.471mol/L C. 0.459mol/L D. 0.429mol/L
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