### Question 19:A solution of isobutyl rubbing alcohol (C₄H₁₀O) contains 40.0 mL of isobutyl alcohol and 60.0 mL of water. The density of isobutyl alcohol is 0.803 g/mL. What is the molarity of the isobutyl alcohol solution?**Solution:**1. **Determine the mass of isobutyl alcohol:**\[ \text{Mass} = \text{Volume} \times \text{Density} \]\[ = 40.0 \, \text{mL} \times 0.803 \, \text{g/mL} \]\[ = 32.12 \, \text{g} \]2. **Calculate the number of moles of isobutyl alcohol (C₄H₁₀O):**\[ \text{Molar mass of } \text{C}_{4}\text{H}_{10}\text{O} = (4 \times 12.01) + (10 \times 1.008) + (1 \times 16.00) \, \text{g/mol} \]\[ = 48.04 + 10.08 + 16.00 \, \text{g/mol} \]\[ = 74.12 \, \text{g/mol} \]\[ \text{Moles} = \frac{\text{Mass}}{\text{Molar Mass}} \]\[ = \frac{32.12 \, \text{g}}{74.12 \, \text{g/mol}} \]\[ = 0.433 \, \text{mol} \]3. **Calculate the total volume of the solution:**\[ \text{Total Volume} = 40.0 \, \text{mL} + 60.0 \, \text{mL} \]\[ = 100.0 \, \text{mL} \]\[ = 0.100 \, \text{L} \]4. **Calculate the molarity of the isobutyl alcohol solution:**\[ \text{Molarity} = \frac{\text{Moles of solute}}{\text{Volume of solution in liters}} \]\[ = \frac{0.

Molarity can be defined as the number of moles of solute present in one liter of solution. Its unit…

A solution of isobutyl rubbing alcohol (C4H100) contains 40.0 mL of isobutyl alcohol and 60.0 mL of water. The density of isobutyl alcohol is 0.803 g/mL. What is the molarity of the isobutyl alcohol solution?

A solution of isobutyl rubbing alcohol (C4H100) contains 40.0 mL of isobutyl alcohol and 60.0 mL of water. The density of isobutyl alcohol is 0.803 g/mL. What is the molarity of the isobutyl alcohol solution?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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