Suppose we are dealing with an ideal gas contained in a cylinder equipped with a movable collection. The gas undergoes different types of thermodynamic transformations while interacting with the environment. Let us consider that the gas undergoes a series of transformations under different conditions of pressure and volume. For all exercises, use the general gas law PV=nRT to perform the calculations and remember to indicate the units correctly.   Exercise 1 - Isothermal Transformation: During an isothermal transformation of an ideal gas, where the temperature T is held constant, the initial pressure of the gas is approximately 1250 Pa, and its final pressure is approximately 630 Pa. For ideal gases R is 0.082 atm.L/mol. K, and the temperature T is 300 K, calculate the initial and final volumes (Vi and Vf) at which the gas is during this isothermal transformation. Remember that 1 atm=101325 Pa Please make it typeable, as handwriting hinders understanding.

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Suppose we are dealing with an ideal gas contained in a cylinder equipped with a movable collection. The gas undergoes different types of thermodynamic transformations while interacting with the environment. Let us consider that the gas undergoes a series of transformations under different conditions of pressure and volume. For all exercises, use the general gas law PV=nRT to perform the calculations and remember to indicate the units correctly.
 
Exercise 1 - Isothermal Transformation:
During an isothermal transformation of an ideal gas, where the temperature T is held constant, the initial pressure of the gas is approximately 1250 Pa, and its final pressure is approximately 630 Pa. For ideal gases R is 0.082 atm.L/mol. K, and the temperature T is 300 K, calculate the initial and final volumes (Vi and Vf) at which the gas is during this isothermal transformation.
Remember that 1 atm=101325 Pa

Please make it typeable, as handwriting hinders understanding.

Expert Solution
Step 1: Give formula for computation

For initial pressure P1 and final pressure P2 also denote initial volume by V1 and final volume V2. Hence for isothermal process

P1.V1=nRT

P2.V2=nRT

Hence we have

V1=nRT/P1

V2=nRT/P2

For n=1 mol and R= 8.31J/mol.K

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