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A gas undergoes two processes. In the first, the volume remains constant at 0.170 m³ and the pressure increases from 2.00x105 Pa to 4.50x105 Pa. The second process is a compression to a volume of 0.130 m³ at a constant pressure of 4.50x105 Pa. Part A Find the total work done by the gas during both processes. Express your answer in joules. 17| ΑΣΦ W = Submit Request Answer ? J

A gas undergoes two processes. In the first, the volume remains constant at 0.170 m³ and the pressure increases from 2.00x105 Pa to 4.50x105 Pa. The second process is a compression to a volume of 0.130 m³ at a constant pressure of 4.50x105 Pa. Part A Find the total work done by the gas during both processes. Express your answer in joules. 17| ΑΣΦ W = Submit Request Answer ? J

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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A gas undergoes two processes. In the first, the volume remains constant at 0.170 m³ and the pressure increases from 2.00x105 Pa to 4.50x105 Pa. The second process is a compression to a volume of 0.130 m³ at a constant pressure of 4.50x105 Pa. Part A Find the total work done by the gas during both processes. Express your answer in joules. IVE ΑΣΦ W = Submit Request Answer ? J
Transcribed Image Text:A gas undergoes two processes. In the first, the volume remains constant at 0.170 m³ and the pressure increases from 2.00x105 Pa to 4.50x105 Pa. The second process is a compression to a volume of 0.130 m³ at a constant pressure of 4.50x105 Pa. Part A Find the total work done by the gas during both processes. Express your answer in joules. IVE ΑΣΦ W = Submit Request Answer ? J
Expert Solution
Step 1

Given data:

The Initial volume for the pressure Vi=0.170 m3

The final volume for the pressure Vf=0.130 m3

The initial pressure Pi=2.00 ×105 Pa

The final pressure Pf=4.50 ×105 Pa

 

It is required to determine the total work by the gas during the process.

 

 

 

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