Got my first answer from Bartleby:95% confidence interval is (xbar−ybar)±tα÷2(s21÷m)+(s22÷n)‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√xbar-ybar±tα÷2s12÷m+s22÷n(114.2−129.7)±(1.7396)(5.012÷9)+(5.362÷9)‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√114.2-129.7±1.73965.012÷9+5.362÷9(−15.5±4.25)-15.5±4.25(-19.75 ,-11.25) Which is not correct, can you do it again? Thanks Suppose u, and µ, are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of braking systems. The data follows: m =9, х %3114.2, s, = 5.01, n = 9, y = 129.7, and s,5.36. Calculatea 95% CI for the difference between true average stopping distances for cars equipped with system 1 and cars equipped with system 2. (Round your answers to two decimal places.)In USE SALT)-20.68-10.32

Name: Got my first answer from Bartleby:95% confidence interval is (xbar−yba
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Description: Got my first answer from Bartleby:95% confidence interval is (xbar−ybar)±tα÷2(s21÷m)+(s22÷n)‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√xbar-ybar±tα÷2s12÷m+s22÷n(114.2−129.7)±(1.7396)(5.012÷9)+(5.362÷9)‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√114.2-129.7±1.73965.012÷9+5.362÷9(−15.5±4.25)-1

we have given that We need to construct the 95\%95% confidence interval for the difference between…

Answered: Suppose u, and H, are true mean…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Got my first answer from Bartleby:

95% confidence interval is

(xbar−ybar)±tα÷2(s21÷m)+(s22÷n)‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√xbar-ybar±tα÷2s12÷m+s22÷n

(114.2−129.7)±(1.7396)(5.012÷9)+(5.362÷9)‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√114.2-129.7±1.73965.012÷9+5.362÷9

(−15.5±4.25)-15.5±4.25

(-19.75 ,-11.25)

Which is not correct, can you do it again? Thanks

Suppose u, and µ, are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of braking systems. The data follows: m =
9, х %3
114.2, s, = 5.01, n = 9, y = 129.7, and s,
5.36. Calculate
a 95% CI for the difference between true average stopping distances for cars equipped with system 1 and cars equipped with system 2. (Round your answers to two decimal places.)
In USE SALT
)
-20.68
-10.32

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