Suppose the series resistors in the example are now 4.00 N and 2.00 N while the parallel resistors are 4.00 N (top) and 2.00 N (bottom), and the battery provides an emf of 76.0 V. (a) Find the equivalent resistance. Ω R `eq (b) Find the currents I, I,, and I2. |A I2

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Chapter1: Units, Trigonometry. And Vectors
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SOLUTION
(a) Find the equivalent resistance of the circuit.
R = R, + R, = 8.0 2 + 4.0 2 = 12.0 0
eq
The 8.0-2 and 4.0-2 resistors are in
series, so use the sum rule to find the
equivalent resistance between a and b.
The 6.0-2 and 3.0-0 resistors are in
1
1
%3D
R
eq
6.0 2
2.0 Q
R,
Reg
parallel, so use the reciprocal-sum rule
R,
3.0 0
to find the equivalent resistance
= 2.0 2
between b and c (don't forget to
invert!).
In the new diagram, figure b, there are
R
-R, + R, -12.0 Ω+ 2.0 Ω-14.0 Ω
eq
now two resistors in series. Combine
them with the sum rule to find the
equivalent resistance of the circuit.
(b) Find the current in each resistor if a 42-V battery is connected between points a and c.
Δν
I =
Find the current in the equivalent
42 V
= 3.0 A
ac =
R
eq
resistor in figure c, which is the total
14 2
current. Resistors in series all carry the
same current, so the value is the
current in the 12-2 resistor in figure b
and also in the 8.0-N and 4.0-2
resistors in figure a.
Calculate the voltage drop AV
para
Δν
para
= IR = (3.0 A)(2.0 2) = 6.0 V
across the parallel circuit, which has an
equivalent resistance of 2.0 Q.
Apply Ohm's law again to find the
Δν
para
6.0 V
= 1.0 A
currents in each resistor of the parallel
6.0 2
R6,0 0
circuit.
Δν
para
6.0 V
I2
= 2.0 A
3.0 2
R3,0 0
LEARN MORE
REMARKS As a final check, note that AV = (6.0 2)I, = (3.0 N)I, = 6.0 V and
bc
AVh = (12 N)I, = 36 V; therefore, AV
= AV + AV = 42 V, as expected.
bc
ас
ab
QUESTION Which of the original resistors dissipates energy at the greatest rate?
O the 8.0 2 resistor
O the 4.0 2 resistor
O the 6.0 Q resistor
O the 3.0 N resistor
EXERCISE
HINTS: GETTING STARTED
| I'M STUCK!
Suppose the series resistors in the example are now 4.00 and 2.00 2 while the parallel resistors are
4.00 N (top) and 2.00 2 (bottom), and the battery provides an emf of 76.0 V.
(a) Find the equivalent resistance.
Reg
(b) Find the currents I, I,, and I,.
I =
A
A
I2 =
A
Transcribed Image Text:SOLUTION (a) Find the equivalent resistance of the circuit. R = R, + R, = 8.0 2 + 4.0 2 = 12.0 0 eq The 8.0-2 and 4.0-2 resistors are in series, so use the sum rule to find the equivalent resistance between a and b. The 6.0-2 and 3.0-0 resistors are in 1 1 %3D R eq 6.0 2 2.0 Q R, Reg parallel, so use the reciprocal-sum rule R, 3.0 0 to find the equivalent resistance = 2.0 2 between b and c (don't forget to invert!). In the new diagram, figure b, there are R -R, + R, -12.0 Ω+ 2.0 Ω-14.0 Ω eq now two resistors in series. Combine them with the sum rule to find the equivalent resistance of the circuit. (b) Find the current in each resistor if a 42-V battery is connected between points a and c. Δν I = Find the current in the equivalent 42 V = 3.0 A ac = R eq resistor in figure c, which is the total 14 2 current. Resistors in series all carry the same current, so the value is the current in the 12-2 resistor in figure b and also in the 8.0-N and 4.0-2 resistors in figure a. Calculate the voltage drop AV para Δν para = IR = (3.0 A)(2.0 2) = 6.0 V across the parallel circuit, which has an equivalent resistance of 2.0 Q. Apply Ohm's law again to find the Δν para 6.0 V = 1.0 A currents in each resistor of the parallel 6.0 2 R6,0 0 circuit. Δν para 6.0 V I2 = 2.0 A 3.0 2 R3,0 0 LEARN MORE REMARKS As a final check, note that AV = (6.0 2)I, = (3.0 N)I, = 6.0 V and bc AVh = (12 N)I, = 36 V; therefore, AV = AV + AV = 42 V, as expected. bc ас ab QUESTION Which of the original resistors dissipates energy at the greatest rate? O the 8.0 2 resistor O the 4.0 2 resistor O the 6.0 Q resistor O the 3.0 N resistor EXERCISE HINTS: GETTING STARTED | I'M STUCK! Suppose the series resistors in the example are now 4.00 and 2.00 2 while the parallel resistors are 4.00 N (top) and 2.00 2 (bottom), and the battery provides an emf of 76.0 V. (a) Find the equivalent resistance. Reg (b) Find the currents I, I,, and I,. I = A A I2 = A
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