Suppose the nutrition information on the package of Matilde's favorite brand of chips states that a serving size of 25 g equal about 12 chips. That means, on average, each chip should weigh 2.08 g. Matilde decides to test the accuracy of this serving size information. She plans to conduct a one-sample t-test with a significance level of a = 0.10 to test the null hypothesis, Ho: H = 2.08, against the alternative hypothesis, H1: µ ± 2.08, where µ is the average weight of a chip. Matilde selects a random sample of unbroken chips to weigh. She does not know the population standard deviation nor the distribution of chip weights, but she has confirmed that her sample does not contain any outliers. The summary statistics for her test are shown in the following table. Sample size Sample mean Sample standard deviation Test statistic Probability value P-value 45 2.04 0.14 -2.076 0.044 Based on these results, complete the following sentences to state the decision and conclusion of the test. Matilde's decision is to the (P = 0.044). There is evidence to the claim that the average weight of is

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Suppose the nutrition information on the package of Matilde's favorite brand of chips states that a serving size of 25 g equals
about 12 chips. That means, on average, each chip should weigh 2.08 g. Matilde decides to test the accuracy of this serving
size information. She plans to conduct a one-sample t-test with a significance level of a = 0.10 to test the null hypothesis,
Họ: H = 2.08, against the alternative hypothesis, H1: µ + 2.08, where µ is the average weight of a chip.
Matilde selects a random sample of unbroken chips to weigh. She does not know the population standard deviation nor the
distribution of chip weights, but she has confirmed that her sample does not contain any outliers. The summary statistics for
her test are shown in the following table.
Sample size Sample mean Sample standard deviation
Test statistic Probability value
P-value
45
2.04
0.14
-2.076
0.044
Based on these results, complete the following sentences to state the decision and conclusion of the test.
Matilde's decision is to
the
(P = 0.044). There is
evidence to
the claim that the average weight
of
is
Transcribed Image Text:Suppose the nutrition information on the package of Matilde's favorite brand of chips states that a serving size of 25 g equals about 12 chips. That means, on average, each chip should weigh 2.08 g. Matilde decides to test the accuracy of this serving size information. She plans to conduct a one-sample t-test with a significance level of a = 0.10 to test the null hypothesis, Họ: H = 2.08, against the alternative hypothesis, H1: µ + 2.08, where µ is the average weight of a chip. Matilde selects a random sample of unbroken chips to weigh. She does not know the population standard deviation nor the distribution of chip weights, but she has confirmed that her sample does not contain any outliers. The summary statistics for her test are shown in the following table. Sample size Sample mean Sample standard deviation Test statistic Probability value P-value 45 2.04 0.14 -2.076 0.044 Based on these results, complete the following sentences to state the decision and conclusion of the test. Matilde's decision is to the (P = 0.044). There is evidence to the claim that the average weight of is
Based on these results, complete the following sentences to state the decision and conclusion of the test.
Matilde's decision is to
the
(P = 0.044). There is
evidence to
the claim that the average weight
isL
Answer Bank
10%
the sample of chips
-2.076
all chips of this brand
prove
one-sample t-test
equal to
some
null hypothesis
2.08 g
greater than
insufficient
45
ассept
reject
0.10
less than
2.04 g
different than
sample proportion
alternative hypothesis
disprove
fail to reject
fail to accept
no
0.14 g
sufficient
support
0.044
of
Transcribed Image Text:Based on these results, complete the following sentences to state the decision and conclusion of the test. Matilde's decision is to the (P = 0.044). There is evidence to the claim that the average weight isL Answer Bank 10% the sample of chips -2.076 all chips of this brand prove one-sample t-test equal to some null hypothesis 2.08 g greater than insufficient 45 ассept reject 0.10 less than 2.04 g different than sample proportion alternative hypothesis disprove fail to reject fail to accept no 0.14 g sufficient support 0.044 of
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