Suppose the math department chair at a large state university wants to estimate the average overall rating, out of five points, that students taking Introductory Statistics gave their lecturers on their end-of-term evaluations. She selects a random sample of 38 evaluations and records the summary statistics shown. Sample Sample Sample standard Population standard Standard Confidence size mean deviation deviation error level C 38 4.0414 1.0501 0.9903 0.1606 90% The department chair determines the standard error using o, the standard deviation calculated from all student evaluations submitted to her department. Assume the Statistics lecturers' ratings have the same standard deviation. Use this information to find the margin of error and the lower and upper bounds of a 90% confidence interval for µ, the mean overall rating students gave their Introductory Statistics lecturers. Round your answers to the nearest hundredth. Margin of error = Lower bound = Upper bound =

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Suppose the math department chair at a large state university wants to estimate the average overall rating, out of five points,
that students taking Introductory Statistics gave their lecturers on their end-of-term evaluations. She selects a random sample
of 38 evaluations and records the summary statistics shown.
Sample Sample
Sample standard
Population standard
Standard
Confidence
size
mean
deviation
deviation
error
level
S
C
38
4.0414
1.0501
0.9903
0.1606
90%
The department chair determines the standard error using o, the standard deviation calculated from all student evaluations
submitted to her department. Assume the Statistics lecturers' ratings have the same standard deviation.
Use this information to find the margin of error and the lower and upper bounds of a 90% confidence interval for µ, the mean
overall rating students gave their Introductory Statistics lecturers. Round your answers to the nearest hundredth.
Margin of error =
Lower bound =
Upper bound =
Transcribed Image Text:Suppose the math department chair at a large state university wants to estimate the average overall rating, out of five points, that students taking Introductory Statistics gave their lecturers on their end-of-term evaluations. She selects a random sample of 38 evaluations and records the summary statistics shown. Sample Sample Sample standard Population standard Standard Confidence size mean deviation deviation error level S C 38 4.0414 1.0501 0.9903 0.1606 90% The department chair determines the standard error using o, the standard deviation calculated from all student evaluations submitted to her department. Assume the Statistics lecturers' ratings have the same standard deviation. Use this information to find the margin of error and the lower and upper bounds of a 90% confidence interval for µ, the mean overall rating students gave their Introductory Statistics lecturers. Round your answers to the nearest hundredth. Margin of error = Lower bound = Upper bound =
Complete the following sentence to state the interpretation of the department chair's confidence interval.
The
that the
of the overall ratings given
on
at the end of the term
Answer Bank
probability is 90%
standard error
standard deviation
is 4.0414
department chair is 90% confident
is between the lower and upper bounds
the student evaluations in the sample
all student evaluations of Statistics lecturers
mean
confidence interval
Transcribed Image Text:Complete the following sentence to state the interpretation of the department chair's confidence interval. The that the of the overall ratings given on at the end of the term Answer Bank probability is 90% standard error standard deviation is 4.0414 department chair is 90% confident is between the lower and upper bounds the student evaluations in the sample all student evaluations of Statistics lecturers mean confidence interval
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