Suppose that Z is the standard normal distribution. a) Use the 68-95 99.7 rule to compute the following probabilities. Note that the answers should be entered as decimals, not percentages. i) P(−1 < Z < 1) = Number ii) P(Z < − 1) = Number iii) P(−3 < Z < −1) = (Enter the exact decimal value according to the 68-95-99.7 rule) (Enter the exact decimal value according to the 68-95-99.7 rule) Number (Enter the exact decimal value according to the 68-95-99.7 rule)

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You are expected to do this question using the 68-95-99.7 rule by hand, that is, without the aid of RStudio.
Suppose that Z is the standard normal distribution.
a) Use the 68 - 95 - 99.7 rule to compute the following probabilities.
Note that the answers should be entered as decimals, not percentages.
i) P(−1 < Z < 1) =
ii) P(Z < − 1) = Number
Number
(Enter the exact decimal value according to the 68-95-99.7 rule)
(Enter the exact decimal value according to the 68-95-99.7 rule)
iii) P(−3 < Z < −1) = Number
b) Using the 68 - 95 - 99.7 rule, find the value of z such that P(Z ≤ z) = 0.9985.
z = Number
(Enter the exact value according to the 68-95-99.7 rule)
(Enter the exact decimal value according to the 68-95-99.7 rule)
Transcribed Image Text:You are expected to do this question using the 68-95-99.7 rule by hand, that is, without the aid of RStudio. Suppose that Z is the standard normal distribution. a) Use the 68 - 95 - 99.7 rule to compute the following probabilities. Note that the answers should be entered as decimals, not percentages. i) P(−1 < Z < 1) = ii) P(Z < − 1) = Number Number (Enter the exact decimal value according to the 68-95-99.7 rule) (Enter the exact decimal value according to the 68-95-99.7 rule) iii) P(−3 < Z < −1) = Number b) Using the 68 - 95 - 99.7 rule, find the value of z such that P(Z ≤ z) = 0.9985. z = Number (Enter the exact value according to the 68-95-99.7 rule) (Enter the exact decimal value according to the 68-95-99.7 rule)
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