Suppose that you have three vectors: fi (x) = 1, f2 (x) = x – 1, and f3 (x) = } (x² – 4x + 2), that make up an orthonormal basis spanning the real vector space of quadratic functions with the inner product: (f; | f;) = L° fi (x) f; (x) e¯ªdx. Suppose we have a derivative operator D = What is (Dfi | f3) =?

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Suppose that you have three vectors: f1 (x) = 1, f2 (x) = x – 1, and f3 (x) = ; (x2 – 4x +2), that make up an orthonormal basis spanning the real vector space of
quadratic functions with the inner product: (f; | f;) = S° fi (x) f; (x) e¯ªdx. Suppose we have a derivative operator D = . What is (Df1 | f3) =?
%3D
6.
dæ
-1
3/4
Оо
Transcribed Image Text:Suppose that you have three vectors: f1 (x) = 1, f2 (x) = x – 1, and f3 (x) = ; (x2 – 4x +2), that make up an orthonormal basis spanning the real vector space of quadratic functions with the inner product: (f; | f;) = S° fi (x) f; (x) e¯ªdx. Suppose we have a derivative operator D = . What is (Df1 | f3) =? %3D 6. dæ -1 3/4 Оо
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