Suppose that you conduct a repeated-measures ANOVA with more than two treatment conditions, and the null hypothesis is rejected. To determine exactly which mean differences are significant and which are not, you conduct post hoc tests. Which of the following statements about the use of the Scheffe test is correct? O The Scheffe test can be conducted using MSerror the denominator of the F-ratio and using dferror as the denominator degrees of freedom to find the critical value. The Scheffe test can be conducted using MS within treatments as the denominator of the F-ratio and using dfwithin treatments as the denominator degrees of freedom to find the critical value. The Scheffe test can't be conducted.

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Post hoc test with repeated measures ANOVA

Suppose that you conduct a repeated-measures ANOVA with more than two treatment conditions, and the null hypothesis is rejected. To determine
exactly which mean differences are significant and which are not, you conduct post hoc tests.
Which of the following statements about the use of the Scheffe test is correct?
The Scheffe test can be conducted using MSerror as the denominator of the F-ratio and using dferror as the denominator degrees of
freedom to find the critical value.
The Scheffe test can be conducted using MS within treatments as the denominator of the F-ratio and using dfwithin treatments as the denominator
degrees of freedom to find the critical value.
The Scheffe test can't be conducted.
Transcribed Image Text:Suppose that you conduct a repeated-measures ANOVA with more than two treatment conditions, and the null hypothesis is rejected. To determine exactly which mean differences are significant and which are not, you conduct post hoc tests. Which of the following statements about the use of the Scheffe test is correct? The Scheffe test can be conducted using MSerror as the denominator of the F-ratio and using dferror as the denominator degrees of freedom to find the critical value. The Scheffe test can be conducted using MS within treatments as the denominator of the F-ratio and using dfwithin treatments as the denominator degrees of freedom to find the critical value. The Scheffe test can't be conducted.
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