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- If the coordinates of point A (x, y) are two random variables with a normal distribution with zero mean(average) variance 4, it is desirable to calculate the probability that the distance of this point from the origin of the coordinates is less than 1.The distribution of certain test scores is a nonstandard normal distribution with a mean of 80 and a standard deviation of 9. What are the values of the mean and a standard deviation after all test scores have been standardized by converting them to z-scores using z=(x-µ)/σ? A) The mean is 100 and the standard deviation is 10 B) The mean is 0 and the standard deviation is 1 C) The mean is 1 and the standard deviation is 0 D) The mean is 10 and the standard deviation is 100Assume that the amount of weight that male college students gain during their freshman year are normally distributed with a. Mean of u= 1.2 kg and a standard deviation of o= 5.1 kg A. If 1 male college student is randomly selected, Find the probability that he gains between 0 and 3 kg during freshman year B. If 25 male college students are randomly selected find the probability that their mean weight gain during freshman year is between 0 and 3 kg why can the normal distribution be used on pet b even though the sample size does not exceed 30?
- The lengths of pregnancies in a small rural village are normally distributed with a mean of 267 days and a standard deviation of 15 days. Let X be the length of a randomly recorded pregnancy in the village. What is the distribution of X? X ~ N (,) Please show the following answers to 4 decimal places. If a pregnancy randomly chosen in the village, find the probability that it lasted less than 244 days. If a pregnancy randomly chosen in the village, find the probability that it lasted between 290 and 298 days. Please show the following answer to a whole day. The 72nd percentile pregnancy length in this village is ___________ days.The population of college students using “normal shoes” is able to complete a particular racecourse in an average of 250 seconds. The standard deviation for this population is 20 seconds and the population is normally distributed. A random sample of 28 college students is given a special pair of new shoes and asked to run the course. The average “race time” for this group is 243 seconds. assume now that the designer of the shoes states that his shoes should improve the times of the user (less time to finish the race). State the hypotheses involved. determine if the hypothesis test is one tailed or two tailed Give the Z scores associated with cut-off points for .01, .05, and .10 (1%, 5%, and 10% respectively). Calculate the Z score for this problem. Based on a cut-off point or alpha level of .05 (5%), what decision would you make about your hypotheses? Explain this decision. Make conclusions regarding the specifics of this study.The number of people who dine at restaurants in Buffalo is normally distributed with a µ = 30 people and = 3 people. (Report both the z-scores and probability) What is the probability that the mean of 7 restaurants will have between 21 and 32 people dining there? z1 = z2 = p(21 > M > 32) = What is the probability that the mean of 13 restaurants will have less than 21 people dining there? z = p(M < 21)= Is the p=0 when the z score is extreme like -10 or 10?
- 7. Let (z,.,) be a random sample from a normal distribution with mean ja and a variance at. Alo let S.. = , - z)* be the sum of squares of the randou sample. State without proof the sampling distribution of the following; (a) t(z) - ạ + b i-, 1,. n, as e positive eal constants. (- ) (b) t(z) - (E) (x) = (e) ti2) - (g) (r) = (e) t(2) = (d) t(a) Er, - E > ( - P (h) 시)- - -1 (-) (e) t(z)Suppose that X~N(5000,400). You're considering taking a simple random sample and calculating the average of your sample. The Central Limit Theorem tells us that the distribution of all possible sample averages is Normally distributed with a mean of 5000. If you took a sample of size n = 100, what is the standard deviation of that sample?If we assume that the distribution of means is normal, then 95% of all sample means a) will fall in the interval m ± 1.96(σm) b) will fall in the interval m ± 1.645(σm) c) will be no more than 1.645(σm) from μ d) will be no more than from 1.96(σm) from μ
- The National Health and Nutrition Examination Survey reported in the recent year, the mean cholesterol level for U.S. adults was 202 with standard deviation of 41 (unit: mg/dl) A simple random sample of 110 adults are chosen. Let x¯ be the sample mean cholesterol with a) The probability that the sample mean cholesterol level of the sample of 110 is greater than 210 is P(x¯>210) = ["", "", "", ""] b) What is the probability that the sample mean is between 190 and 200: P(190<x¯<200) = ["", "", "", ""]Suppose that X~N(5000,400). You're considering taking a simple random sample and calculating the average of your sample. The Central Limit Theorem tells us that the distribution of all possible sample averages is Normally distributed with a mean of 5000. If you took a sample of size n = 10000, what is the standard deviation of that sample?The average wait time to get seated at a popular restaurant in the city on a Friday night is 12 minutes. Is the mean wait time greater for men who wear a tie? Wait times for 13 randomly selected men who were wearing a tie are shown below. Assume that the distribution of the population is normal. 13, 13, 11, 13, 13, 13, 13, 10, 12, 13, 13, 10, 13 What can be concluded at the the αα = 0.05 level of significance level of significance? The null and alternative hypotheses would be: H0 = (p,u) (<,>,=,not equal) to _____ H1 = (p,u) (<,>,=,not equal) to _____ The test statistic (t,z) = ___ The p-value = _____ Thus, the final conclusion is that ... The data suggest that the population mean wait time for men who wear a tie is not significantly more than 12 at αα = 0.05, so there is statistically insignificant evidence to conclude that the population mean wait time for men who wear a tie is more than 12. The data suggest the population mean is not significantly more than 12…