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- myopenmath.com М МубрenMath b Statistics Question | bartleby P(Z=0.6) - Wolfram|Alpha G 99 confidence interval - Google Search Objective: Probability involving means For X with u = 4, o = 6 and a sample size of 26, P(X < 1) = Note: round your z score to two decimals places O 0.6915. O 0.0054. 0.3085. 0.9946. none of the above answers are accurate because of a failed assumption. Submit Questionreview(37a): A psycharist hypothesized that patients with schizopherina , who stayed in the hospital the longest would score the lowest on a mental oreintation test. She collected data for six patients with shizophernia which are listed below. Years of Hospitalization Mental oreienation 6 5 7 3 12 2 5 7 3 8 8 4 test the hypothesis at 5% level of signifcance usinf the 5 step procedure..Round your answer to 2 decimal placesTest the claim that the mean GPA of night students is larger than 2 at the 0.025 significance level. The null and alternative hypothesis would be: Но: и 0.5 Но: n> 2 H1: µ > 2 H1:p + 0.5 H1:µu # 2 H1:p > 0.5 H1:p < 0.5 H1: µ < 2 The test is: left-tailed right-tailed two-tailed Based on a sample of 40 people, the sample mean GPA was 2.01 with a standard deviation of 0.06 The p-value is: (to 2 decimals) Based on this we: Reject the null hypothesis OFail to reject the null hypothesis
- Population 1 Population 2 Use the given statistics to complete parts (a) and (b). Assume that the populations are normally distributed. (a) Test whether H, > H, at the a = 0.01 level of significance for the given sample data. (b) Construct a 90% confidence interval about u, -H2. 28 16 45.3 43.2 9.7 6.7 (a) Identify the null and alternative hypotheses for this test. O A. Ho: H1 > H2 O B. H: H1 =H2 OC. Hg: H1 = H2 H;: H1 # H2 O F. Ho: H1 H2. O B. Do not reject Hg. There is not sufficient evidence at the a = 0.01 level of significance to conclude that u, > H2. O C. Do not reject H,. There is sufficient evidence at the a= 0.01 level of significance to conclude that u, > H2- O D. Reject Hn. There is not sufficient evidence at the a= 0.01 level of significance to conclude that u, > H2- (b) The 90% confidence interval about u, - H, is the range from a lower bound of to an upper bound of (Round to three decimal places as needed.)Statistics - MA3113 B-IC-Edgenuity.com 95% CI Z-Value P-value (0.113, 3.00 0.267) 0.0027 5/25/22, 12:44 PM A carnival game is designed so that approximately 10% of players will win a large prize. If there is evidence that the percentage differs significantly from this target, then adjustments will be made to the game. To investigate, a random sample of 100 players is selected from the large population of all players. Of these players, 19 win a large prize. The question of interest is whether the data provide convincing evidence that the true proportion of players who win this game differs from 0.10. The computer output gives the results of a z-test for one proportion. Test and CI for One Proportion Test of p= 0.1 vs p = 0.1 Sample X N Sample 1 19 100 Р 0.19 What conclusion should be made at the a = 0.05 level? O Because the P-value < a = 0.05, there is convincing evidence that the true proportion of players who win this game differs from 0.10. O Because the P-value < a = 0.05, there is…q10c A six-sided die is rolled 120 times (results listed in table below). Face Value Frequency 1 15 2 29 3 16 4 15 5 30 6 15 Determine if the die is fair (if it is fair, what is the expected frequency of each face value through 120 rolls?). Test at the 1% level. (vii) Comparing p-value and α value, which is the correct decision to make for this hypothesis test? A. Reject Ho B. Fail to reject Ho C. Accept Ho D. Accept HA Enter letter corresponding to correct answer. (viii) Select the statement that most correctly interprets the result of this test: A. The result is not statistically significant at .01 level of significance. Sufficient evidence exists to support the claim that distribution of observed rolls of the die does NOT fit the distribution of expected rolls. There is sufficient evidence to support the hypothesis that the die is NOT fair. B. The result is statistically significant at .01 level of…
- #18[Statistics: Confidence Intervals and Hypothesis Testing] How do you solve this, will upvote if done quicklyonsider the following results for two independent random samples taken from two populations. Sample 1 Sample 2 n 1 = 50 n 2 = 30 x 1 = 13.1 x 2 = 11.2 σ 1 = 2.3 σ 2 = 3 What is the point estimate of the difference between the two population means? (to 1 decimal) Provide a 90% confidence interval for the difference between the two population means (to 2 decimals). Use z-table.( , ) Provide a 95% confidence interval for the difference between the two population means (to 2 decimals). Use z-table. If your answer is negative, enter minus (-) sign.( , )