Suppose that the random variables Y1 and Y2 have joint probability density function, fV1, y2), giver fV1, y2) = {YiY2, 0< yı < y2, Yi +y2 < 2 elsewhere 0, Derive the marginal density of Y1. Derive the marginal density of Y2.(Hint: this will have to broken down into two parts!!!) Derive the conditional density of Y2 given Y1 = y1. Find P(Y2 < 1.1 | Y1 = .60). %3D

Q: Find z given that P(.24 <Z <z) = .12

A:

Q: Assume P(Z>b)=0.22 for some number b. Without finding the value of b, what is P(Z<-b)?

A: From the provided information,P (Z&gt;b) = 0.22

Q: P(z<2.25)=

A: Given Information: To find out Pz&lt;2.25

Q: What is P( -1.03 < Z < 0.57 )?

A: The question is about standard normal distribution Introduction : Standard normal distribution. Z is…

Q: Compute the indicated quantity. P(A | B) = 0.3, P(B) = 0.8. Find P(A n B). P(A n B) =

A: Using conditional probability we get:P(A|B)=0.3P(A∩B)P(B)=0.3P(A∩B)=0.3P(B)P(A∩B)=0.3×0.8 [given…

Q: Find P(-1.40 < Z < 0)     .4192     .1259     .4357     .8907

A: Solution: Let Z be the standard normal random variable with mean μ=0 and standard deviation σ=1…

Q: P(Z > 0.98)=

A:

Q: To find P(x<2.35) where do you shade?

A: Left side

Q: P(z< ( Or equal to ) z0) = 0.7054

A:

Q: X 0 1 2 3 P(X = x) |0.512 0.384 0.096 0.008 Find P(more than 2 identifications are incorrect).

A: From the provided information, x 0 1 2 3 P (X = x) 0.512 0.384 0.096 0.008…

Q: 9/State the Sufficient condition for the best apfraximation ant Prove t

A:

Q: P(Z<1.89) (less than or equal to)

A: Given that.   X~N( 0 , 1 )   μ=0  , ?=1 (for standard normal distribution)    Z-score =( x - μ )/?

Q: find P (Z > 1.21) = find P (Z < 1.60) = find P (0.59 < Z < 1.78) =

A: 1) P (Z &gt; 1.21) =?

Q: Find P(-1.18 < z < 1.18).

A: From the provided information, P (-1.18 &lt; z &lt; 1.18)

Q: find P(-1.2<Z<1.9)

A:

Q: What is P(X>6)?

A:

Q: P(x < 17.872)

A: Let's take the given  Sample size n=33 from a population, with mean=16 and standard deviation=8.4…

Q: Find P(X < 0.3)

A:

Q: P (z &lt; -0.02) =?

A:

Q: If the P(A)=0.4 ,P(B)=0.2,P(A | B)= UB)-0,5 Than P(B/A) is :0 :0 C NIO

A: Option D is the answer.

Q: if  Let P(C) = 0.2, Let P(D) = 0.3, Let P(C | D) = 0.4  how do you find P(D | C)

A:

Q: P(1.15 < Z < 2.77) =

A: X~N( 0 , 1 )   μ=0 , ?=1 (for standard normal distribution)   Z-score =( x - μ )/?

Q: P(z < -2.61)

A: Z score = -2.61 Left tailed test

Q: p(-c<z<c)=0.9464

A: P(-c&lt;z&lt;c)=0.9464

Q: Calculate P(z<-1.2)

A: The z-score is standard normal variable with mean 0 and standard deviation 1.

Q: P(0.51 ≤ Z ≤ 1.4) =

A: Draw the normal curve and shade the area between z=0.51 and z=1.4.

Q: z −1

A: To find the required area, use the standard normal table. The required probability value is, P(z…

Q: (h) P(1.26 ≤ Z ≤ 2.50) (1) P(1.90 ≤ Z) (1) P(|Z| ≤ 2.50)

A: It is given that the standard normal random variable Z with mean 0 and variance 1.   Note: The…

Q: Find P(1.73< Z < 2.16)

A:

Q: P(−0.71 ≤ Z ≤ 1.34) =

A: Draw the normal curve and shade the area between z=-0.71 and z=1.34.

Q: P(X ≤ 1). n = 5, p = 0.6

A:

Q: Consider throwing a die 5 times. Let X be the number of times the outcome is less than 3. Find P(X =…

A: Let p be the probability of getting number less than 3  Result used:  nCr=n!/(r!(n-r)!)…

Q: P(0.74<Z<2.11)

A: Let Z be the standard normal variable with parameters μ=0  and σ=1 The probability is,

Q: Find P (1.23 <z <2.35)

A:

Q: P(- c ≤ Z ≤ c)=0.9399

A: We have given that  P(- c ≤ Z ≤ c)=0.9399 From the given information we have to find the value of c

Q: ind P(|Z| ≤ 2.5). (round to three decimal places.

A: given data  standard normal curve Z~N(0,1) P(|Z|≤2.5) = ?

Q: Find  P( −2.25 < z < 1.65) , use the table as given with question paper.

A:

Q: Find P(-1.96 <Z< 1.96) PDF 0.0 0.2 0.4

A: Explanation:   The probability that P (-1.96 &lt;Z &lt;1.96) is: P (-1.96 &lt;Z &lt;1.96) =…

Q: p(0.7 <z < 1.31) =

A: Answer - Find P( 0.7 &lt; Z &lt; 1.31)  = ?

Q: what is p(z<?)=0.88

A: