Suppose that the function qux is guaranteed to return an integer between -365 and 350 inclusive. If you wanted to compare the return value of this function against the target value -27 with a structure that would send the flow of control down a different path depending on whether the return value was less than or greater than or equal to the target value then which of the following branching structures would be the best approach? This question is internally recognized as variant 250. Q6) fragment 1 contains the correct code fragment 2 contains the correct code fragment 3 contains the correct code fragment 4 contains the correct code fragment 5 contains the correct code fragment 6 contains the correct code fragment 7 contains the correct code fragment 8 contains the correct code none of the above # code fragment 1 starts on the next linefooqux ()elif foo < -27:=path 1 of 3# control flow path 2 of 3elif foo == -27:# control flow path 3 of 3# control flowelif foo > -27:# code fragment 2 starts on the next linefooqux ()if foo < -27:=# control flow path 1 of 3elif foo > -27:# control flow path 2 of 3else:# control flow path 3 of 3# code fragment 3 starts on the next linefoo =qux ()if foo < -27:# control flowpath 1 of 3# control flow path 2 of 3== -27:# control flowpath 3 of 3starts on the next lineif foo > -27:if foo# code fragment 4qux ()fooif foo < -27:=# control flow path 1 of 3elif foo > -27:# control flow path 2 of 3elif foo == -27:# control flow path 3 of 3# code fragment 5 starts on the next linefoo =qux ()if foo < -27:# control flow path 1 of 3else:# control flow path 2 of 3path 3 of 3# code fragment 6 starts on the next linefoo = qux ()if foo < -27:if foo == -27:# control flow# control flow path 1 of 3elif foo > -27:# control flow path 2 of 3if foo == -27:# control flow path 3 of 3# code fragment 7 starts on the next linefoo =qux ()if foo < -27:# control flow path 1 of 3if foo > -27:# control flow path 2 of 3else:# control flow path 3 of 3# code fragment 8 starts on the next linefoo =qux ( )if foo < -27:# control flowpath 1 of 3if foo > -27:# control flow path 2 of 3elif foo -27:# control flow path 3 of 3==

Here we are given multiple condition fragments, we need to find which one will be the best approach…

Answered: Suppose that the function qux is…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Related questions

Concept explainers

Question

Suppose that the function qux is guaranteed to return an integer between -365 and 350 inclusive. If you wanted to compare the return value of this function against the target value -27 with a structure that would send the flow of control down a different path depending on whether the return value was less than or greater than or equal to the target value then which of the following branching structures would be the best approach? This question is internally recognized as variant 250.

Q6)

	fragment 1 contains the correct code
	fragment 2 contains the correct code
	fragment 3 contains the correct code
	fragment 4 contains the correct code
	fragment 5 contains the correct code
	fragment 6 contains the correct code
	fragment 7 contains the correct code
	fragment 8 contains the correct code
	none of the above

# code fragment 1 starts on the next line
foo
qux ()
elif foo < -27:
=
path 1 of 3
# control flow path 2 of 3
elif foo == -27:
# control flow path 3 of 3
# control flow
elif foo > -27:
# code fragment 2 starts on the next line
foo
qux ()
if foo < -27:
=
# control flow path 1 of 3
elif foo > -27:
# control flow path 2 of 3
else:
# control flow path 3 of 3
# code fragment 3 starts on the next line
foo =
qux ()
if foo < -27:
# control flow
path 1 of 3
# control flow path 2 of 3
== -27:
# control flow
path 3 of 3
starts on the next line
if foo > -27:
if foo
# code fragment 4
qux ()
foo
if foo < -27:
=
# control flow path 1 of 3
elif foo > -27:
# control flow path 2 of 3
elif foo == -27:
# control flow path 3 of 3
# code fragment 5 starts on the next line
foo =
qux ()
if foo < -27:
# control flow path 1 of 3
else:
# control flow path 2 of 3
path 3 of 3
# code fragment 6 starts on the next line
foo = qux ()
if foo < -27:
if foo == -27:
# control flow
# control flow path 1 of 3
elif foo > -27:
# control flow path 2 of 3
if foo == -27:
# control flow path 3 of 3
# code fragment 7 starts on the next line
foo =
qux ()
if foo < -27:
# control flow path 1 of 3
if foo > -27:
# control flow path 2 of 3
else:
# control flow path 3 of 3
# code fragment 8 starts on the next line
foo =
qux ( )
if foo < -27:
# control flow
path 1 of 3
if foo > -27:
# control flow path 2 of 3
elif foo -27:
# control flow path 3 of 3
==

Expert Solution

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.

Similar questions