Suppose that the following processes arrive for execution at the times indicated. Eachprocess has the shown priorities and will run for the amount of time listed (all times are inms)ProcessArrival TimeBurst TimePriority QueueP1153P2203P32020P425102P53052P635151To schedule the execution of these process, a preemptive multi-level queue scheduler isdesigned to apply the following policy at each decision instant (namely whenever a newprocess arrives and whenever a burst completes execution):• Serve the process at the highest priority queue first• If two processes are in the same queue:. If they have different remaining time, follow the SRTF policyo If they have same remining time, follow a RR policy (slice time = 2 ms)Given the above:1. Show the scheduling order of the bursts using a Gantt chart.

In priority scheduling, we schedule processes based on given priority. The processes with the…

Answered: Suppose that the following processes…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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For the following processes, estimate average waiting time for priotiry scheduling combines with round robin scenario.Consiider quanta of 1s. Process Burst TimePriority P1 10 3 P2 1 P3 2 2 P4 1 Ps 2 P6 3
In concurrent programming, a "critical section" is a part of a multi-process program that a) may not be concurrently executed by more than one of the program's thread. Let us consider a 2 processes solution: do { flag[i] = TRUE; while(flag[j]); %wait CRITICAL SECTION flag[i] = FALSE; REMAINDER SECTION } while (TRUE); Pseudo-code of $P_i$ (the one of $P_j$ is symmetric) } Does the given solution sattisfy the mutual exclusion requirement? Explain (a (i) í simple 'yes-no' answer is NOT enough. What is the mutual exclusion requirement? Why is (not?) sattisfied?) (ii) (iii) your answer (no point without a valid simluation) (iv) deadlock), how can you modify the given solution to make it working? Does the given solution sattisfy the progress requirement? Explain Does the given solution have the risk of deadlock? Make a simulation to support if your answer to the previous question is positive (i.e. Yes, there is the risk of
Part I Assume that the ready queue has just received for processes: P1, P2, P3, P4, in that order. All at time 0. The CPU execution times for these processes are as follows: Process Execution Time P1 P2 P3 P4 13 8 15 6 Draw the Gantt chart and calculate the metric listed in parentheses for each of the following scheduling algorithms: 1. First Come, First Served (Total Wait Time) 2. Shortest Job First (Total Wait Time) 3. Round Robin, with a time quantum of 5 ms (Total Wait and Response Times) Part II Now assume that P1 arrives in the ready queue at time 0, P2 arrives at time 4, P3 arrives at time 10, and P4 arrives at time 20. The CPU execution times for the processes are the same as in Part I: Process Execution Time P1 P2 P3 P4 P1 13 P2 8 P3 15 P4 6 Draw the Gantt chart and calculate the total wait time for each of the following scheduling algorithms: 1. Shortest Job First 2. Shortest Remaining Time Next (remember, this is a preemptive algorithm) 3. Preemptive priority with the…
Suppose that the following processes arrive for execution at the time given below. Each process will run for the amount of time listed. Calculate average turnaround and average waiting time for these processes under Shortest remaining time first (SRTF)(preemptive) scheduling AlgorithmHints: turnaround time: The interval from the time of arrival of a process to the time of completionWaiting time: The sum of the periods spent waiting by a process in the ready queue
In Round Robin scheduling, when three processes have to enter the ready-queue at the same instant, if one process (A) has just finished 1/o, the other (B) has been pre-empted from CPU due to expiration of its time quantum and the third (C) has just started, which one will be inserted last (i.e. with lowest priority)? O The process that has just finished I/O. O One of the three will be randomly selected. O The process that has been pre-empted from CPU due to expiration of its time quantum. O The process that has just started.
Q10 In symmetric multiprocessor scheduling using private queues, when the scheduler running on a processor seeks to change its workload because it has no tasks to run, it performs a specific type of action called a Enter your answer here Q11 Consider the following pseudo-code implementation of a semaphore wait operation. void wait() { disable interrupts; sem value = sem value- 1; if ( sem value < 0) { block the calling process, adding it to sem_queue; schedule a process from the ready queue; enable interrupts; Is this code free of race conditions on a SMP? O Yes O No
If you are working with scheduling policies, you are requested to investigate the variation of round robin in which a process that has used its full time quantum is returned to the end of the READY queue, while one that has used half of its time quantum is returned to the middle of the queue and one that has used one-fourth of its time quantum goes to a place one-fourth of the distance away from the beginning of the queue. 5.1 Explain the advantages and disadvantages of this scheduling policy. 5.2 Identify the user group that would find this most advantageous. 5.3 Describe the unique threats to a data centre posed by disgruntled employees. Describe how you would identify such people, if possible, and how you would protect your system from these threats. 5.4 What are the parameters that affect the efficiency of the round robin?
Q.4: Design a multilevel queue that satisfies the following requirements: a) uses time quantum that equals 10 to complete short burst time (10); i.e., use aging technique. Discuss how your design works through an example you suggest?
Given the following processes that arrived on the system as indicated in the table. The table also mention the burst time and priority of each one. Process Arrival time Burst time Priority P1 12 3 P2 7 1 P3 2 2 How the system will allocate the CPU based on Round Robin with time quantum equal to 3– suppose that all processes arrived at time 0. Processes are selected to enter the queue according to priority. So, instead of processes entering the queue in the order P1, P2 and P3. They will enter according to their priority from highest to Lowest. So, they will enter the queue in the order P2, P3, P1. Afterwards, you execute the Round Robins algorithm and draw the Gantt chart.
Can you fix and change the code of Splitting the processes into different queues based on priority, FCFS Scheduling, RR Scheduling, and Priority Scheduling into new code? The new code is provided in the image below and please show the output. Thank you!Code: #include <iostream>#include <queue>#include <string>#include <vector> struct Process { int processId; int burstTime; int priority;}; void print_gantt_chart(const std::vector<std::pair<int, int>>& gantt_chart) { std::cout << "Gantt Chart:" << std::endl; std::cout << "----------------------------------------------------------------------------" << std::endl; std::cout << "| "; for (const auto& process : gantt_chart) { std::cout << "P" << process.first << " | "; } std::cout << std::endl; std::cout << "----------------------------------------------------------------------------" <<…
First_Come_First_Serve Sample Code void calcAvg (int burst_time[4], int waiting_time[4], int turnaround_time[4]) { int i, j; int avgwait=0; int avgTurn=e; void fcfs(int burst_time[4]) int waiting_time[4]; int turnaround_time[4]; int i,j; printf("\nProcess\t\tBurst Time\tWaiting Time\tTurnaround Time"); for (i=@; i<4; i++) waiting_time[@]=e; //calculating waiting time for (i=1; i<4; i++) avgWait += waiting_time[i]; avgTurn += turnaround_time[i]; waiting_time[i]=e; for (j=0; j
Question 1 Two processes need to acquire 3 mutexes in order to access a particular shared queue. The mutexes are numerically ordered. Process 1 acquires the mutexes in 1, 2, 3 order and Process 2 acquires them in 3, 2, 1 order. If a process tries to acquire a mutex held by the other process, a conflict is detected, both processes release their mutexes, wait for some (random) time, and try again. Does the proposed scheme guarantee the processes can always successfully access the shared queue? Yes, but at the cost of efficiency Yes, no livelock is possible because the mutexes are numerically ordered No, starvation is possible No, priority inversion is possible

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