Given the following processes that arrived on the system as indicated in the table. The table alsomention the burst time and priority of each one.Process Arrival time Burst time PriorityP1123P271P322How the system will allocate the CPU based on Round Robin with time quantum equal to3– suppose that all processes arrived at time 0. Processes are selected to enter the queueaccording to priority. So, instead of processes entering the queue in the order P1, P2 andP3. They will enter according to their priority from highest to Lowest. So, they will enterthe queue in the order P2, P3, P1. Afterwards, you execute the Round Robins algorithmand draw the Gantt chart.

At time =3, P2 starts executing P2 0 3…

Answered: Given the following processes that…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Similar questions

Suppose that an operating system supports two kinds of sequential processes: high-priority interactive processes, and low-priority non-interactive processes. The behavior of the high-priority processes is to alternate between periods of computation of duration Tc and periods of blocking (waiting for input) of duration Tb. The behavior of the low-priority processes is to compute constantly, with no blocking. The operating system’s scheduling policy is round-robin with a quantum q, where Tc < q. Scheduling decisions are made only when a quantum expires, or when the running process blocks. The scheduler selects a low-priority process to run only if no high-priority processes are ready. Suppose there is one high-priority process and one low-priority process in the system, and that both processes will run for a long time. For what fraction of the time does the low-priority process run?
For Question, put your answer in the following blanks. Note: You must put answer only, no need to put the unit. One answer per blank.
Subject: Operating Systems
Consider a single-server queueing system with arrival and service details as: Interarrival times 3 2 6 2 45 Service times 2 5 5845 Prepare simulation table using Event Scheduling / Time Advance Algorithm for the given data. Stop simulation when the clock reaches 20. In the simulation table, include the following: 1) B: Cumulative Busy Time 2) MQ: Cumulative Maximum number of Customers in Queue 3) F: Cumulative number of Customers who spent more than 3 minutes in the system. 1
Suppose there are four processes (P1 - P4) with respective arrival times of 0, 10, 30, and 40, and burst times of 30, 20, 50, and 20 ms. These processes are scheduled from a ready queue on first come first served. The average waiting time is?
Textbook examples show a task that is waiting at a rendezvous for another to task to arrive in a continuous loop, What non-busy wait method is really being used? an explicit wait in put in place. A wait stack is checked after each interaction instead of a constant repeat check as in a loop every iteration, a continue is checked a queue is searched every iteration.
Concurrent Processes / Monitors select which is true options: a CV (condition variable) queues in a monitor store suspended processes waiting on the corresponding condition. b The "Signal and Wait" approach (Hoare semantics) leads to more efficient implementation and reduces the number of context switches. c Two or more processes can be active in the same monitor simultaneously. d When the "Signal and Continue"-approach (Mesa semantics) is applied, the signaling process P continues executing. e The monitor-based solution to the Dining-Philosophers problem discussed in class is restricted to 5 philosophers.

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