Suppose that P(X > 3) = 0.3, then O None of these a=0.44; b=0.26 a=0.42; b=0.29 a=0.34; b=0.26
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- Suppose that a decision maker's risk atitude toward monetary gains or losses x given by the utility function(x) = (50,000+x) 34/2. Suppose that a decision maker has the choice of buying a lottery ticket for $5, or not. Suppose that the lottery winning is $1,000,000, and the chance of winning is one in a thousand. Then..... O The decision maker should not buy the ticket, as the utility from not buying is 223.6, and the expected utility from buying is 223.59. The decision maker should not buy the ticket, as the utility from not buying is 223.6067, and the expected utility from buyingis 223.6065. O The decision maker should buy the ticket, as the utility from not buying 223.60, and the utility from buying is 224.4. The decision maker should buy the ticket, as the utility from not buying 223.6065, and the utility from buying is 223.6067.An automobile service facility specializing in engine tune-ups knows that 60% of all tune-ups are done on four-cylinder automobiles, 30% on six-cylinder automobiles, and 10% on eight-cylinder automobiles. Let X = the number of cylinders on the next car to be tuned. What is the pmf of X?A. Fail to reject H, because the P-value, 0.0433, is greater than a = 0.05. B. Fail to reject H, because the P-value, 0.0433, is less than a = 0.05. C. Reject Ho because the P-value, 0.0433, is greater than a = 0.05, D. Reject Ho because the P-value, 0.0433, is less than a= 0.05. Do you reject or fail to reject H, at the 0.10 level of significance? A. Fail to reject Ho because the P-value, 0.0433, is less than a = 0.10.
- The management of the local zoo wants to know if all of their animal exhibits are equally popular. If there is significant evidence that some of the exhibits are not being visited frequently enough, then changes may need to take place within the zoo. A tally of visitors is taken for each of the following animals throughout the course of a week, and the results are contained in the following table. At a = 0.025, determine whether there is sufficient evidence to conclude that some exhibits are less popular than others. Animal Exhibits at the Zoo Elephants Lions/Tigers Giraffes Zebras Monkeys Birds Reptiles Number of 164 166 172 188 165 139 142 visitors Copy Data Step 4 of 4: Draw a conclusion and interpret the decision. Next Prev 国 Tables E Keypad Answer Keyboard Shortcuts We fail to reject the null hypothesis and conclude that there is sufficient evidence at a 0.025 level of significance that some exhibits are less popular than others. We fail to reject the null hypothesis and conclude…6. Given that P(A) = 0.40, P(B) = 0.35, and P(AB) = 0.10, find; P(A) P(AUB) P(An B9) a. b. C.Sean thinks that he has a special relationship with the number 6. In particular, Sean thinks that he would roll a 6 with a fair 6-sided die more often than you'd expect by chance alone. Suppose pis the true proportion of the time Sean will roll a 6. (a) State the null and alternative hypotheses for testing Sean's claim. (Type the symbol "p" for the population proportion, whichever symbols you need of "", "-", "not =" and express any values as a fraction e.g. p = 1/3) Ho= Ha (b) Now suppose Sean makes n = 30 rolls, and a 6 comes up 6 times out of the 30 rolls. Determine the P-value of the test, giving your answer to 4 decimal places. Please use 3 decimal places in your test statistic when finding the P-value. P-value = ⠀⠀ (c) Answer the question: Does this sample provide evidence at the 5 percent level that Sean rolls a 6 more often than you'd expect? (Type: Yes or No) 4
- Are Republicans less likely than Democrats to display the American flag in front of their residence on the Fourth of July? 409 of the 660 Republicans surveyed display the flag on the Fourth of July and 472 of the 687 Democrats surveyed display the flag on the Fourth of July. What can be concluded at the a = 0.05 level of significance? For this study, we should use Select an answer a. The null and alternative hypotheses would be: Ho: Select an answer v Select an ahswer vSelect an answer v (please enter a decimal) H1: [Select an answer Select an answer v Select an answer v (Please enter a decimal) b. The test statistic ? v (please show your answer to 3 decimal places.) !! c. The p-value (Please show your answer to 4 decimal places.) d. The p-value is ? va e. Based on this, we should Select an answer v the null hypothesis.Matt thinks that he has a special relationship with the number 2. In particular, Matt thinks that he would roll a 2 with a fair 6-sided die more often than you'd expect by chance alone. Suppose p is the true proportion of the time Matt will roll a 2. (a) State the null and alternative hypotheses for testing Matt's claim. (Type the symbol "p" for the population proportion, whichever symbols you need of "", "=", "not =" and express any values as a fraction e.g. p = 1/3) Ho p= 1/6 = Ha= p > 1/6 (b) Now suppose Matt makes n = 34 rolls, and a 2 comes up 7 times out of the 34 rolls. Determine the P-value of the test: P-value = | (c) Answer the question: Does this sample provide evidence at the 5 percent level that Matt rolls a 2 more often than you'd expect? (Type: Yes or No) noSuppose P(A) = 0.7 and P(B) = 0.5. If P(A and B) = 0.3, with the help of a Venn diagram, we can estimate that P(A or B) will be a) more than 0.7 b) less than 0.5 c) more than 1.2 d) less than 0.3
- Suppose the following information is known P[A] = 0.8, P[B] = 0.5, P[A and B] = 0.40. The values for P[B|A] and P[A|B] are respectively: (a) It cannot be determined. (b) 0.65, 0.75 (c) 0.65, 0.70 (d) 0.50, 0.80 (e) 0.50, 0.75If S = {a, b, c} with P(a) = P(b) and P(c) = 0.36, find P(a).P(a) =Which combination would lead you to Reject H₂? a = .05 p-value = .045 a = .01 p-value = .059 O a = .05 p-value = .059 O a = .01 p-value = .045
