Suppose that one in six smartphone users have fallen prey to cyber-attack. We use a sample of 159 smartphone users. a-1. What is the expected value and the standard error of the sample proportion? Note: Round "Expected value" to 2 decimal places and "Standard error" to 4 decimal places.   a-2. Is it appropriate to use the normal distribution approximation for the sample proportion? multiple choice Yes, because np ≥ 5 and n(1 - p) ≥ 5 Yes, because n ≥ 30 No, because np ≥ 5 and n(1 - p) ≥ 5 No, because n < 30 b. What is the probability that more than 24% of smartphone users in the sample have fallen prey to cyber-attack? Note: Round final answer to 2 decimal places.

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