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Patients with an average blood pressure of 140 and above are classified as having hypertension. Over the course of 8 visits, the patient's blood pressure is measured as 137 143 141 133 We would like to rule out the possibility that the patient has hypertension, so we put the data into statistical analysis software: N 8 144 130 131 140 Reading the output, we find that Mean 137.4 • The sample size is n = • The sample mean is = • The sample standard deviation is SD = . From this we can calculate the standard error to SE • Calculate the t-score t = x 140 SE • The degrees of freedom for the t-score is n-1= SD √n Note that the observed sample mean is is less than than 140. This could mean that the patient does not have hypertension, or they could have hypertension, but the small numbers were due to sampling variability. To see if this is the case, we will test the hypothesis that μ = 140 against the alternative that u 140 at a significance level of a = 0.05. = Std. Dev. 5.5

Patients with an average blood pressure of 140 and above are classified as having hypertension. Over the course of 8 visits, the patient's blood pressure is measured as 137 143 141 133 We would like to rule out the possibility that the patient has hypertension, so we put the data into statistical analysis software: N 8 144 130 131 140 Reading the output, we find that Mean 137.4 • The sample size is n = • The sample mean is = • The sample standard deviation is SD = . From this we can calculate the standard error to SE • Calculate the t-score t = x 140 SE • The degrees of freedom for the t-score is n-1= SD √n Note that the observed sample mean is is less than than 140. This could mean that the patient does not have hypertension, or they could have hypertension, but the small numbers were due to sampling variability. To see if this is the case, we will test the hypothesis that μ = 140 against the alternative that u 140 at a significance level of a = 0.05. = Std. Dev. 5.5

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Patients with an average blood pressure of 140 and above are classified as having hypertension. Over the course of 8 visits, the patient's blood pressure is measured as 137 143 141 133 We would like to rule out the possibility that the patient has hypertension, so we put the data into statistical analysis software: N 8 Reading the output, we find that 144 130 131 140 • The sample size is n = • The sample mean is • The sample standard deviation is SD = Mean 137.4 Calculate the t-score t From this we can calculate the standard error to be SE = = x 140 SE • The degrees of freedom for the t-score is n − 1 = - = Note that the observed sample mean is is less than than 140. This could mean that the patient does not have hypertension, or they could have hypertension, but the small numbers were due to sampling variability. To see if this is the case, we will test the hypothesis that μ = 140 against the alternative that μ 140 at a significance level of a = : 0.05. = SD √n Std. Dev. 5.5
Transcribed Image Text:Patients with an average blood pressure of 140 and above are classified as having hypertension. Over the course of 8 visits, the patient's blood pressure is measured as 137 143 141 133 We would like to rule out the possibility that the patient has hypertension, so we put the data into statistical analysis software: N 8 Reading the output, we find that 144 130 131 140 • The sample size is n = • The sample mean is • The sample standard deviation is SD = Mean 137.4 Calculate the t-score t From this we can calculate the standard error to be SE = = x 140 SE • The degrees of freedom for the t-score is n − 1 = - = Note that the observed sample mean is is less than than 140. This could mean that the patient does not have hypertension, or they could have hypertension, but the small numbers were due to sampling variability. To see if this is the case, we will test the hypothesis that μ = 140 against the alternative that μ 140 at a significance level of a = : 0.05. = SD √n Std. Dev. 5.5
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