Suppose that it is given to you that f′(x)=(x+4)(12−x)(16−x)f′(x)=(x+4)(12−x)(16−x) Then the first relative extremum (from the left) for f(x)f(x) occurs at x=x=  The function f(x)f(x) has a relative        at this point. The second relative extremum (from the left) for f(x)f(x) occurs at x=x=  The function f(x)f(x) has a relative        at this point. The third relative extremum (from the left) for f(x)f(x) occurs at x=x=  The function f(x)f(x) has a relative        at this point. The first inflection point (from the left) for f(x)f(x) occurs at x=x=

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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 Suppose that it is given to you that

f′(x)=(x+4)(12−x)(16−x)f′(x)=(x+4)(12−x)(16−x)


Then the first relative extremum (from the left) for f(x)f(x) occurs at x=x= 
The function f(x)f(x) has a relative        at this point.

The second relative extremum (from the left) for f(x)f(x) occurs at x=x= 
The function f(x)f(x) has a relative        at this point.

The third relative extremum (from the left) for f(x)f(x) occurs at x=x= 
The function f(x)f(x) has a relative        at this point.

The first inflection point (from the left) for f(x)f(x) occurs at x=x= 

The second inflection point (from the left) for f(x)f(x) occurs at x=x=

ƒ'(x) = (x + 4)(12 — x)(16 — x)
0
Then the first relative extremum (from the left) for f(x) occurs at x =
The function f(x) has a relative min ✓at this point.
0
The second relative extremum (from the left) for f(x) occurs at x =
The function f(x) has a relative max ✓ at this point.
The third relative extremum (from the left) for f(x) occurs at x = 0
The function f(x) has a relative min at this point.
The first inflection point (from the left) for f(x) occurs at x = 0
The second inflection point (from the left) for f(x) occurs at x =
0
Transcribed Image Text:ƒ'(x) = (x + 4)(12 — x)(16 — x) 0 Then the first relative extremum (from the left) for f(x) occurs at x = The function f(x) has a relative min ✓at this point. 0 The second relative extremum (from the left) for f(x) occurs at x = The function f(x) has a relative max ✓ at this point. The third relative extremum (from the left) for f(x) occurs at x = 0 The function f(x) has a relative min at this point. The first inflection point (from the left) for f(x) occurs at x = 0 The second inflection point (from the left) for f(x) occurs at x = 0
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