Suppose that, in a comparison of two holiday companies’ customers, of the 75 who went with Happy Days Tours, 45 said they were satisfied, while 48 of the 90 who went with Fly by Night Holidays were satisfied. Test at a 2.5% significance level whether there is a difference in the true proportion of satisfied customers for the two companies?
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Suppose that, in a comparison of two holiday companies’ customers, of the 75 who went with Happy Days Tours, 45
said they were satisfied, while 48 of the 90 who went with Fly by Night Holidays were satisfied. Test at a 2.5% significance
level whether there is a difference in the true proportion of satisfied customers for the two companies?
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- According to the most recent General Social Survey, 70% of adults watch TV nightly. A researcher believes that the proportion of college students who watch TV nightly is less than this. To test this claim the research samples 400 college students and finds that 276 watch TV nightly. At the 0.05 level of significance does this data provide evidence to suggest that the proportion of college students who watch TV nightly is less than 70%?Suppose a marriage counselor believes that the proportion of married couples with three personality preferences in common is significantly different from the known value of 35%. A survey randomly given to her current and former clients found 130 of 432 couples who sharedthree personality preferences. Does this indicate that the proportion is significantly different (either higher or lower)? Use a 1% level of significance to test her claim and show all work.The ages of the 5 officers for a school club are 18, 18, 17, 16, and 15. The median of the ages of the officers is 17.0. The table displays all possible samples of size 2 and the corresponding median for each sample. Using the medians in the table, is the sample median an unbiased estimator? Yes, 50% of the sample medians are 17 or more, and 50% are below. Yes, the mean of the sample medians is 16.8, which is the same as the mean age of the officers. No, the mean of the sample medians is 16.8, which is not the same as the median age of the officers. No, the median of the sample medians is 16.75, which is not the same as the median age of the officers.
- A study was conducted to determine the proportion of people who dream in black and white instead of color. Among 297 people over the age of 55, 75 dream in black and white, and among 310 people under the age of 25, 19 dream in black and white. Use a 0.05 significance level to test the claim that the proportion of people over 55 who dream in black and white is greater than the proportion for those under 25. Complete parts (a) through (c) below. a. Identify the test statistic. z= 6.51 (Round to two decimal places as needed.) Identify the P-value. P-value = 3.770o (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? The P-value is greater than the significance level of a = 0.05, so fail to reject the null hypothesis. There is insufficient evidence to support the claim that the proportion of people over 55 who dream in black and white is greater than the proportion for those under 25. b. Test the claim by constructing an appropriate confidence…A study was conducted to determine the proportion of people who dream in black and white instead of color. Among 318 people over the age of 55, 77 dream in black and white, and among 298 people under the age of 25, 16 dream in black and white. Use a 0.05 significance level to test the claim that the proportion of people over 55 who dream in black and white is greater than the proportion for those under 25. Complete parts (a) through (c) below. H4: P1 P2 H: P1 #P2 O D. Ho: P1 SP2 H1: P1#P2 O E. Ho: P1 P2 H1: P1 = P2 O F. Ho: P1 =P2 H1: P1 #P2 Identify the test statistic. z= 6.52 (Round to two decimal places as needed.) Identify the P-value. P-value = 0.000 (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? The P-value is less than the significance level of a = 0.05, so reject the null hypothesis. There is sufficient evidence to support the claim that the proportion of people over 55 who dream in black and white is greater than the proportion…Restaurant Bill by GenderA study compared the cost of restaurant meals when people pay individually versus splitting the bill as a group. In the experiment half of the people were told they would each be responsible for individual meals costs and the other half were told the cost would be split equally among the six people at the table. In the study, the diners were also chosen so that half the people at each table were female and half were male. We can test for a difference in mean meal cost between females (n1=24, x¯1=44.46, s¯1=15.48) and males (n2=24, x¯2=43.75, s2=14.81).Let group 1 and group 2 be the meal costs for females and males, respectively. state the null and alternative hypotheses calculate the relevant test statistic find the p-value
- A study was conducted to determine the proportion of people who dream in black and white instead of color. Among 295 people over the age of 55, 64 dream in black and white, and among 312 people under the age of 25, 13 dream in black and white. Use a 0.05 significance level to test the claim that the proportion of people over 55 who dream in black and white is greater than the proportion for those under 25. Complete parts (a) through (c) below. a. Test the claim using a hypothesis test. Consider the first sample to be the sample of people over the age of 55 and the second sample to be the sample of people under the age of 25. What are the null and alternative hypotheses for the hypothesis test? O A. Ho: P₁ = P₂ H₁: P₁ P2 O B. Ho: P₁ P₂ H₁: P₁ = P2 O E. Ho: P₁ SP₂ H₁: P₁ P2 OC. Ho: P₁ P2 H₁: P₁ P2 OF. Ho: P₁ H₁: P₁ P₂ P2A study was conducted to determine the proportion of people who dream in black and white instead of color. Among 294 people over the age of 55, 63 dream in black and white, and among 300 people under the age of 25, 19 dream in black and white. Use a 0.05 significance level to test the claim that the proportion of people over 55 who dream in black and white is greater than the proportion for those under 25. Complete parts (a) through (c) below. a. Test the claim using a hypothesis test. Consider the first sample to be the sample of people over the age of 55 and the second sample to be the sample of people under the age of 25. What are the null and alternative hypotheses for the hypothesis test? A. Ho: P₁ = P2 H₁: P₁ P2 D. Ho: P₁ P2 H₁: P₁ P2 OB. Ho: P1 P2 H₁: P₁ P2 O E. Ho: P1 H₁: P₁ P2 P2 O C. Ho: P₁ P2 H₁: P₁ = P2 OF. Ho: P₁ P2 H₁: P₁ P26. In December 2001, 38% of adults with children under the age of 18 reported that their family ate dinner together 7 nights a week. In a recent poll, 403 out of 1122 randomly selected adults with children under the age of 18 reported that their family ate dinner together 7 nights a week. Has the proportion of families with children under the age of 18 who eat dinner together 7 nights a week decreased? Use a 0.05 level of significance.
- The results of a random sample of students by type of school and their attitudes on safety steps taken by the school staff are shown in the table below. At the 5% significance level, can you conclude that attitudes about safety steps taken by the school staff are related to the type of school? School staff has School Type Taken all steps for student safety Taken some steps for student safety Public 40 51 Private 64 34The personality characteristics of business leaders (e.g., CEOS) are related to the operations of the businesses that they lead (Oreg & Berson, 2018). Traits like openness to experience are related to positive financial outcomes and other traits are related to negative financial outcomes for their businesses. Suppose that a board of directors is interested in evaluating the personality of their leadership. Among a sample of n = 16 managers, the sample mean of the openness to experiences dimension of personality was M = 4.50. Assuming that u = 4.24 and o = 1.05 (Cobb-Clark & Schurer, 2012), use a two-tailed hypothesis test with a = .05 to test the hypothesis that this company's business leaders' openness to experience is different from the population. Standard Normal Distribution Mean - 0.0 Standard Deviation 1.0 .7198 .1401 .1401 -3.0 -2.0 -1.0 0.0 1.0 2.0 3.0 -1.08 1.08 Step 1. Ho: ; H;: a = .05. Step 2. The critical region consists of Step 3. For these data the standard error is and…As part of a dissertation at Oklahoma State University, Ota Lutz investigated the effect of teaching science to children using NASA materials versus traditional science instructions. Here are the final exam scores for the students in the two :groups Traditional: 64, 75, 72, 65, 53, 54, 71, 95, 73, 71 NASA :55, 80, 77, 76, 70, 61, 85, 67, 70, 84, 70 Is there a difference in the mean test scores for the ?two groups The null hypothesis, the alternative hypothesis and the kind of it (right- tailed, left- tailed or two- tailed), are Ho : Hirad = UNASA H: Hirad # HN ASA .The alternative hypothesis is two-tailed Ho : Hırad = HNASA H1: Hirad # HNASA .The null hypothesis is two-tailed Ho : Hirad = HNASA H: Hirad HNASA .The alternative hypothesis is right-tailed
