Suppose that ƒ(x) and g(x) are two functions and we know that: ƒ(-3) = 2 g(-3) = 5 ƒ'(−3) = −1 g'(−3) = −2 Find the following: (ƒ − g)'(−3) : (g-f)'(-3) = (fg)'(-3) = (4) '(−3) If k(x)= = f(x) x² then k'(−3)

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A: f(-6)=-2,f'(-6)=-18,g(-6)=-12,g'(-6)=7,h'(-6)=?

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A: Explanation of the solution is given below...

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Q: 1. f(x) = 4x - 17

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