Suppose that during each step, the leg of the student in Example 14.11 swings through a total distance of 2.0 m. At the end of the swing, this foot rests on the ground for 0.2 s before the other leg begins its swing. a. At what speed does this student walk? (Think carefully about how far forward the student moves at each step.) b. The swinging leg reaches its maximum speed at the bottom of its arc. How many times faster is this maximum leg speed (measured with respect to the ground) than the average walking speed?  SEE EX 14.11 in ATTACHED PICTURE

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Suppose that during each step, the leg of the student in Example 14.11 swings through a total distance of 2.0 m. At the end of the swing, this foot rests on the ground for 0.2 s before the other leg begins its swing. a. At what speed does this student walk? (Think carefully about how far forward the student moves at each step.) b. The swinging leg reaches its maximum speed at the bottom of its arc. How many times faster is this maximum leg speed (measured with respect to the ground) than the average walking speed? 

SEE EX 14.11 in ATTACHED PICTURE

Finding the frequency of a swinging leg B10
EXAMPLE 14.11
A student in a biomechanics lab measures the length of his leg,
from hip to heel, to be 0.90 m. What is the frequency of the pen-
dulum motion of the student's leg? What is the period?
The expression for the frequency is similar to that for the simple
pendulum, but with an additional numerical factor of 3/2 inside
the square root. The numerical value of the frequency is
STRATEGIZE Equation 14.29 for the period of a physical pen-
dulum contains the center-of-gravity distance d and the moment
of inertia I. We’ll need to make some simplifying assumptions to
estimate these lengths.
(9.8 m/s²
1
f=
3
2V090 m)
= 0.64 Hz
The period is
PREPARE We can model a human leg reasonably well as a rod of
uniform cross section, pivoted at one end (the hip). Recall from
Chapter 7 that the moment of inertia of a rod pivoted about its
end is mL?. The center of gravity of a uniform leg is at the mid-
point, so d= L/2.
1
T=
= 1.6 s
ASSESS Notice that we didn’t need to know the mass of the leg
to find the period. The period of a physical pendulum does not
SOLVE The frequency of a physical pendulum is given by Equa- depend on the mass, just as it doesn't for the simple pendulum.
tion 14.29. Before we put in numbers, we will use symbolic rela-
tionships and simplify:
The period depends only on the distribution of mass. When you
walk, swinging your free leg forward to take another stride corre-
sponds to half a period of this pendulum motion. For a period of
1.6 s, this is 0.80 s. For a normal walking pace, one stride in just
under one second sounds about right.
1
f=
|mgd
mg(L/2)
3 g
1
1
I
2
2 L
Transcribed Image Text:Finding the frequency of a swinging leg B10 EXAMPLE 14.11 A student in a biomechanics lab measures the length of his leg, from hip to heel, to be 0.90 m. What is the frequency of the pen- dulum motion of the student's leg? What is the period? The expression for the frequency is similar to that for the simple pendulum, but with an additional numerical factor of 3/2 inside the square root. The numerical value of the frequency is STRATEGIZE Equation 14.29 for the period of a physical pen- dulum contains the center-of-gravity distance d and the moment of inertia I. We’ll need to make some simplifying assumptions to estimate these lengths. (9.8 m/s² 1 f= 3 2V090 m) = 0.64 Hz The period is PREPARE We can model a human leg reasonably well as a rod of uniform cross section, pivoted at one end (the hip). Recall from Chapter 7 that the moment of inertia of a rod pivoted about its end is mL?. The center of gravity of a uniform leg is at the mid- point, so d= L/2. 1 T= = 1.6 s ASSESS Notice that we didn’t need to know the mass of the leg to find the period. The period of a physical pendulum does not SOLVE The frequency of a physical pendulum is given by Equa- depend on the mass, just as it doesn't for the simple pendulum. tion 14.29. Before we put in numbers, we will use symbolic rela- tionships and simplify: The period depends only on the distribution of mass. When you walk, swinging your free leg forward to take another stride corre- sponds to half a period of this pendulum motion. For a period of 1.6 s, this is 0.80 s. For a normal walking pace, one stride in just under one second sounds about right. 1 f= |mgd mg(L/2) 3 g 1 1 I 2 2 L
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