Suppose that BC financial aid alots a textbook stipend by claiming that the average textbook at BC bookstore costs $ 60.92. You want to test this claim. The null and alternative hypothesis in symbols would be: a) H0:p≤60.92H1:p > 60.92 b) H0:μ=60.92; H1:μ≠60.92 c) H0:μ ≥ 60.92; H1:μ < 60.92 d) H0:μ ≤ 60.92; H1:μ > 60.92 e) H0:p≥60.92; H1:p<60.92 f) H0:p=60.92; H1:p≠60.92 The null hypothesis in words would be: The average price of all textbooks from the store is $$ 60.92 The average price of textbooks in a sample is $$ 60.92 The average of price of all textbooks from the store is less than $$ 60.92. The proportion of all textbooks from the store that are less than 60.92 is equal to 50% The average of price of all textbooks from the store is greater than $$ 60.92. Based on a sample of 110 textbooks at the store, you find an average of 65.72 and a standard deviation of 17. The point estimate is: ______ (to 3 decimals) The 95 % confidence interval (use z*) is: _____ to ______ (to 3 decimals) Based on this we either Fail to reject the null hypothesis Reject the null hypothesis

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Suppose that BC financial aid alots a textbook stipend by claiming that the average textbook at BC bookstore costs $ 60.92. You want to test this claim.

The null and alternative hypothesis in symbols would be:

a) H0:p≤60.92H1:p > 60.92

b) H0:μ=60.92; H1:μ≠60.92

c) H0:μ ≥ 60.92; H1:μ < 60.92

d) H0:μ ≤ 60.92; H1:μ > 60.92

e) H0:p≥60.92; H1:p<60.92

f) H0:p=60.92; H1:p≠60.92


The null hypothesis in words would be:

  • The average price of all textbooks from the store is $$ 60.92
  • The average price of textbooks in a sample is $$ 60.92
  • The average of price of all textbooks from the store is less than $$ 60.92.
  • The proportion of all textbooks from the store that are less than 60.92 is equal to 50%
  • The average of price of all textbooks from the store is greater than $$ 60.92.



Based on a sample of 110 textbooks at the store, you find an average of 65.72 and a standard deviation of 17.

The point estimate is: ______ (to 3 decimals)

The 95 % confidence interval (use z*) is: _____ to ______ (to 3 decimals)

Based on this we either

  • Fail to reject the null hypothesis
  • Reject the null hypothesis
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