Suppose that AB is the diameter of a circle with çenter O and that C is a point on one of the two arcs joining A and B. Show that CÁ and CB are orthogonal without using coordinates. A В
Suppose that AB is the diameter of a circle with çenter O and that C is a point on one of the two arcs joining A and B. Show that CÁ and CB are orthogonal without using coordinates. A В
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter10: Analytic Geometry
Section10.4: Analytic Proofs
Problem 19E: Use the analytic method to decide what type of triangle is formed when the midpoints of the sides of...
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![**Title: Orthogonality in a Circle with Diameter**
**Objective:**
To demonstrate that the line segments \( \overrightarrow{CA} \) and \( \overrightarrow{CB} \) are orthogonal without using coordinate geometry.
**Problem Statement:**
Suppose that \( AB \) is the diameter of a circle with center \( O \), and that \( C \) is a point on one of the two arcs joining \( A \) and \( B \). Prove that \( \overrightarrow{CA} \) and \( \overrightarrow{CB} \) are orthogonal.
**Diagram Explanation:**
1. The diagram shows a circle with center \( O \) and diameter \( AB \).
2. Point \( A \) is positioned on the left end of the diameter, and point \( B \) is on the right end.
3. There is a vector \( \overrightarrow{u} \) originating from the center \( O \) to \( B \), and \( -\overrightarrow{u} \) from \( O \) to \( A \).
4. Point \( C \) is marked on the upper arc of the circle, above the diameter \( AB \).
5. Vector \( \overrightarrow{v} \) points from \( O \) to \( C \).
**Proof Approach Without Coordinates:**
1. **Central Angle Subtends a Right Angle:**
- In any circle, an angle subtended by the diameter (i.e., angle \( \angle ACB \)) is a right angle (90 degrees). This is a well-known result from the properties of a circle.
2. **Orthogonality:**
- Two vectors (or line segments in this context) are orthogonal if the angle between them is 90 degrees.
- Here, \( \angle ACB = 90^\circ \), implying that \( \overrightarrow{CA} \) and \( \overrightarrow{CB} \) form a right angle with each other.
Based on these geometric principles, we can conclude that vectors \( \overrightarrow{CA} \) and \( \overrightarrow{CB} \) are indeed orthogonal.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faba5746d-e0e8-46ca-a0bb-ec14000055d1%2F61828d79-d494-4490-b2a7-80bc4e46b522%2Fhc44ndr_processed.png&w=3840&q=75)
Transcribed Image Text:**Title: Orthogonality in a Circle with Diameter**
**Objective:**
To demonstrate that the line segments \( \overrightarrow{CA} \) and \( \overrightarrow{CB} \) are orthogonal without using coordinate geometry.
**Problem Statement:**
Suppose that \( AB \) is the diameter of a circle with center \( O \), and that \( C \) is a point on one of the two arcs joining \( A \) and \( B \). Prove that \( \overrightarrow{CA} \) and \( \overrightarrow{CB} \) are orthogonal.
**Diagram Explanation:**
1. The diagram shows a circle with center \( O \) and diameter \( AB \).
2. Point \( A \) is positioned on the left end of the diameter, and point \( B \) is on the right end.
3. There is a vector \( \overrightarrow{u} \) originating from the center \( O \) to \( B \), and \( -\overrightarrow{u} \) from \( O \) to \( A \).
4. Point \( C \) is marked on the upper arc of the circle, above the diameter \( AB \).
5. Vector \( \overrightarrow{v} \) points from \( O \) to \( C \).
**Proof Approach Without Coordinates:**
1. **Central Angle Subtends a Right Angle:**
- In any circle, an angle subtended by the diameter (i.e., angle \( \angle ACB \)) is a right angle (90 degrees). This is a well-known result from the properties of a circle.
2. **Orthogonality:**
- Two vectors (or line segments in this context) are orthogonal if the angle between them is 90 degrees.
- Here, \( \angle ACB = 90^\circ \), implying that \( \overrightarrow{CA} \) and \( \overrightarrow{CB} \) form a right angle with each other.
Based on these geometric principles, we can conclude that vectors \( \overrightarrow{CA} \) and \( \overrightarrow{CB} \) are indeed orthogonal.
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