Suppose that AB is the diameter of a circle with çenter O and that C is a point on one of the two arcs joining A and B. Show that CÁ and CB are orthogonal without using coordinates. A В

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Chapter10: Analytic Geometry
Section10.4: Analytic Proofs
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**Title: Orthogonality in a Circle with Diameter**

**Objective:**
To demonstrate that the line segments \( \overrightarrow{CA} \) and \( \overrightarrow{CB} \) are orthogonal without using coordinate geometry.

**Problem Statement:**
Suppose that \( AB \) is the diameter of a circle with center \( O \), and that \( C \) is a point on one of the two arcs joining \( A \) and \( B \). Prove that \( \overrightarrow{CA} \) and \( \overrightarrow{CB} \) are orthogonal.

**Diagram Explanation:**

1. The diagram shows a circle with center \( O \) and diameter \( AB \).
2. Point \( A \) is positioned on the left end of the diameter, and point \( B \) is on the right end.
3. There is a vector \( \overrightarrow{u} \) originating from the center \( O \) to \( B \), and \( -\overrightarrow{u} \) from \( O \) to \( A \).
4. Point \( C \) is marked on the upper arc of the circle, above the diameter \( AB \).
5. Vector \( \overrightarrow{v} \) points from \( O \) to \( C \).

**Proof Approach Without Coordinates:**

1. **Central Angle Subtends a Right Angle:**
    - In any circle, an angle subtended by the diameter (i.e., angle \( \angle ACB \)) is a right angle (90 degrees). This is a well-known result from the properties of a circle.
   
2. **Orthogonality:**
    - Two vectors (or line segments in this context) are orthogonal if the angle between them is 90 degrees.
    - Here, \( \angle ACB = 90^\circ \), implying that \( \overrightarrow{CA} \) and \( \overrightarrow{CB} \) form a right angle with each other.

Based on these geometric principles, we can conclude that vectors \( \overrightarrow{CA} \) and \( \overrightarrow{CB} \) are indeed orthogonal.
Transcribed Image Text:**Title: Orthogonality in a Circle with Diameter** **Objective:** To demonstrate that the line segments \( \overrightarrow{CA} \) and \( \overrightarrow{CB} \) are orthogonal without using coordinate geometry. **Problem Statement:** Suppose that \( AB \) is the diameter of a circle with center \( O \), and that \( C \) is a point on one of the two arcs joining \( A \) and \( B \). Prove that \( \overrightarrow{CA} \) and \( \overrightarrow{CB} \) are orthogonal. **Diagram Explanation:** 1. The diagram shows a circle with center \( O \) and diameter \( AB \). 2. Point \( A \) is positioned on the left end of the diameter, and point \( B \) is on the right end. 3. There is a vector \( \overrightarrow{u} \) originating from the center \( O \) to \( B \), and \( -\overrightarrow{u} \) from \( O \) to \( A \). 4. Point \( C \) is marked on the upper arc of the circle, above the diameter \( AB \). 5. Vector \( \overrightarrow{v} \) points from \( O \) to \( C \). **Proof Approach Without Coordinates:** 1. **Central Angle Subtends a Right Angle:** - In any circle, an angle subtended by the diameter (i.e., angle \( \angle ACB \)) is a right angle (90 degrees). This is a well-known result from the properties of a circle. 2. **Orthogonality:** - Two vectors (or line segments in this context) are orthogonal if the angle between them is 90 degrees. - Here, \( \angle ACB = 90^\circ \), implying that \( \overrightarrow{CA} \) and \( \overrightarrow{CB} \) form a right angle with each other. Based on these geometric principles, we can conclude that vectors \( \overrightarrow{CA} \) and \( \overrightarrow{CB} \) are indeed orthogonal.
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