Suppose that a simple random sample is taken from a normal population having a standard deviation of 15 for thepurpose of obtaining a 95% confidence interval for the mean of the population. Complete parts (a) through (c) below.Click here to view Page 1 of the table of areas under the standard normal curve.Click here to view Page 2 of the table of areas under the standard normal curve.a. If the sample size is 9, obtain the margin of error.The margin of error for a sample size of 9 is(Round to two decimal places as needed.)0.b. Repeat part (a) for a sample size of 36.The margin of error for a sample size of 36 is.(Round to two decimal places as needed.)c. Can you guess the margin of error for a sample size of 144? Explain your reasoning.The margin of error for a sample size of 144 is(Round to two decimal places as needed.)Explain your reasoning.Because the sample sizeby a factor of from part (h) to part (c) the margin of error wasTime Remaining: 01:03:51Next

Population standard deviation, σ=15 Confidence level, CL=0.95

Answered: Suppose that a simple random sample is…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Use the data and table below to test the indicated claim about the means of two populations. Assume that the two samples are independent simple randor samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Make sure you identify all values. An Exercise Science instructor at IVC was interested in comparing the resting pulse rates of students who exercise regularly and the pulse rates of those who de not exercise regularly. Independent simple random samples of 16 students who do not exercise regularly and 12 students who exercise regularly were selected and the resting pulse rates (in beats per minute) were recorded. The summary statistics are presented in the table below. Is there compelling statistical evidence that the mean resting pulse rate of people who do not exercise regularly is greater than the mean resting pulse rate of people who exercise regularly? Use a significance value of 0.05. Two-Sample T-Test Sample…
The weight of items produced by a machine is normally distributed with a mean of 8 ounces and a standard deviation of 2 ounces.Refer to Exhibit 6-5. What is the random variable in this experiment? a. 8 ounces b. Weight of items produced by a machine c. Normal distribution d. 2 ounces
A 0.1 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is less than 0.5. Assume that sample data consists of 78 girls in 169 births, so the sample statistic of 613 results in a z score that is 1 standard deviation below 0. Complete parts (a) through (h) below.Click here to view page 1 of the Normal table. LOADING... Click here to view page 2 of the Normal table. LOADING...Question content area bottomPart 1a. Identify the null hypothesis and the alternative hypothesis. Choose the correct answer below.A.H0: p≠0.5H1: p<0.5B.H0: p=0.5H1: p≠0.5C.H0: p=0.5H1: p<0.5D.H0: p=0.5H1: p>0.5Part 2b. What is the value of α?α=enter your response here (Type an integer or a decimal.)Part 3c. What is the sampling distribution of the sample statistic? Normal distribution Student (t) distribution χ2Part 4d. Is the test two-tailed, left-tailed, or right-tailed? Right-tailed…
A 0.01 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is different from 0.5. Assume that sample data consists of 55 girls in 100 births, so the sample statistic of 1120 results in a z score that is 1 standard deviation above 0. Complete parts (a) through (h) below.Click here to view page 1 of the Normal table. LOADING... Click here to view page 2 of the Normal table. LOADING...Question content area bottomPart 1a. Identify the null hypothesis and the alternative hypothesis. Choose the correct answer below.A.H0: p=0.5H1: p≠0.5B.H0: p=0.5H1: p>0.5C.H0: p=0.5H1: p<0.5D.H0: p≠0.5H1: p=0.5Part 2b. What is the value of α?α=enter your response here (Type an integer or a decimal.)Part 3c. What is the sampling distribution of the sample statistic? χ2 Normal distribution Student (t) distribution
Choose the appropriate statistical test. When computing, be sure to round each answer as indicated. A dentist wonders if depression affects ratings of tooth pain. In the general population, using a scale of 1-10 with higher values indicating more pain, the average pain rating for patients with toothaches is 6.8. A sample of 30 patients that show high levels of depression have an average pain rating of 7.1 (variance 0.8). What should the dentist determine? 1. Calculate the estimated standard error. (round to 3 decimals). [st.error] 2. What is thet-obtained? (round to 3 decimals). 3. What is the t-cv? (exact value) 4. What is your conclusion? Only type "Reject" or Retain"
Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.05 significance level to test for a difference between the measurements from the two arms. What can be concluded? 143 140 141 136 133 Right arm Left arm 180 174 192 140 144 In this example, . is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the measurement from the right arm minus the measurement from the left arm. What are the null and alternative hypotheses for the hypothesis test? O A. Ho: Ha = 0 O B. Ho: Hd #0 0 = Prt :H O D. Ho: Hd =0 H O C. Ho: Ha 0 Identify the test statistic. t%3D (Round to two decimal places as needed.) Identify the P-value. P-value (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test?…
A data set includes 106 body temperatures of healthy adult humans having a mean of 98.9°F and a standard deviation of 0.63°F. Construct a 99% confidence interval estimate of the mean body temperature of all healthy humans. What does the sample suggest about the use of 98.6°F as the mean body temperature? Click here to view a t distribution table. LOADING... Click here to view page 1 of the standard normal distribution table. LOADING... Click here to view page 2 of the standard normal distribution table. LOADING... Question content area bottom Part 1 What is the confidence interval estimate of the population mean μ? enter your response here°F<μ<enter your response here°F (Round to three decimal places as needed.)
For the specified margin of error and confidence level, obtain a sample size that will ensure a margin of error of at most the one specified. margin of error = 0.03; confidence level = 99% Click here to view Page 1 of the table of areas under the standard normal curve. Click here to view Page 2 of the table of areas under the standard normal curve. n=1842 (Round up to the nearest integer.)
Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.01 significance level to test for a difference between the measurements from the two arms. What can be concluded? Right arm 147 151 120 132 138 Left arm 177 166 173 145 149 In this example, μd is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the measurement from the right arm minus the measurement from the left arm. What are the null and alternative hypotheses for the hypothesis test? Identify the test statistic. t= (Round to two decimal places as needed.)
A random sample of 40 college students has a mean earnings of $3120 with a standard deviation of $677 over the summer months. Determine whether a normal distribution or a t-distribution should be used or whether neither of these can be used to construct a confidence interval. Question 2 options: Cannot use normal distribution or t-distribution. Use normal distribution. Use the t-distribution.
I need help with this one please thank you
A 0.05 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is greater than 0.5. Assume that sample data consists of 78 girls in 144 births, so the sample statistic of 1324 results in a z score that is 1 standard deviation above 0. Complete parts (a) through (h) below.Click here to view page 1 of the Normal table. LOADING... Click here to view page 2 of the Normal table. LOADING...Question content area bottomPart 1a. Identify the null hypothesis and the alternative hypothesis. Choose the correct answer below.Part 4d. Is the test two-tailed, left-tailed, or right-tailed? Left-tailed Right-tailed Two-tailedPart 5e. What is the value of the test statistic?The test statistic is enter your response here. (Type an integer or a decimal.)Part 6f. What is the P-value?The P-value is enter your response here. (Round to four decimal places as needed.)

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