Suppose that a manufactured product has 2 defects per unit of product inspected. probabilities of finding a product without any defect, 3 defects, and 4 defects. (Given e Using Poisson's distribution, calculate the e-2 =0.135)
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- The dean of a university estimates that the mean number of classroom hours per week for full-time faculty is 11.0. As a member of the student council, you want to test this claim. A random sample of the number of classroom hours for eight full-time faculty for one week is shown in the table below. At a = 0.01, can you reject the dean's claim? Complete parts (a) through (d) below. Assume the population is normally distributed. 12.1 8.9 11.8 8.4 7.2 10.1 12.1 8.74. For a Binomial distribution of 10 trails, P(X-3) = 3P(x-4). Find the standard deviation of the distribution and P(X=2). Solution:Suppose that the number of traffic accident claims received in a month is modeled by Poisson distribution with intensity λ = 4. Assume that each traffic accident claim takes values $150, $300 or $450 equally likely. Calculate the probability that the total traffic accident claim amounts to exactly $1500.
- Trying to find variance. his equation is Prob(x)*[x-e(x)]^2. Just need an example to get me started.Original question is: A call center recieves an average of 10 calls per hour. Assuming the number of calls received follows the poisson distribution, determine the probability of each of the discrete outcomes below. Then calculate the variance component for each one using the standard formula for the variance of a discrete random variable. At the end, take the sum of both columns. Table: Poisson Distribution Table Calls Density Variance 0 0.00% 1 0.05% 2 0.23% 3 0.76% 4 1.89% 5 3.78% 6 6.31% 7 9.01% 8 11.26% 9 12.51% 10 12.51% 11 11.37% 12 9.48% 13 7.29% 14 5.21% 15 3.47% 16 2.17% 17 1.28% 18 0.71% 19 0.37% 20 0.19% 21 0.09% 22 0.04% 23 0.02% 24 0.01% 25 0.00% 26 0.00% 27 0.00% 28 0.00% 29 0.00% 30 0.00% Sum 100.00%23. Find the cumulant generating function of gamma distribution and obtain various cumulants.Can you help with part b without using Chebyshev's theorem
- 34) If a population exhibits a skew of -5.00 and an excess kurtosis of 5.00 which of the following is true? The population mean exceeds the median. The population variance exceeds the standard deviation. The population standard deviation exceeds the variance. The population median equals the mean. The population median exceeds the mean.The Poisson distribution gives the probability for the number of occurrences for a "rare" event. Now, let x be a random variable that represents the waiting time between rare events. Using some mathematics, it can be shown that x has an exponential distribution. Let x > 0 be a random variable and let β > 0 be a constant. Then y = 1 β e−x/β is a curve representing the exponential distribution. Areas under this curve give us exponential probabilities. If a and b are any numbers such that 0 < a < b, then using some extra mathematics, it can be shown that the area under the curve above the interval [a, b] is the following. P(a < x < b) = e−a/β − e−b/β Notice that by definition, x cannot be negative, so, P(x < 0) = 0. The random variable x is called an exponential random variable. Using some more mathematics, it can be shown that the mean and standard deviation of x are the following. μ = β and σ = β Note: The number e = 2.71828 is used throughout…Suppose that the number of customers entering a bank in one hour is a Poisson random variable and suppose that P(X=0)=0.02. Find the mean and variance of the variable. X: Number of customers entering a bank in one hour E(X)= Answer (Give the exact answer) V(X)= Answer (Give the exact answer) What is the probability that 5 customers will enter in two hours? Answer: Note: Answer with at least 4 decimal places
