Suppose events A B, C, and D have probabilities as followsB TotalsC 0 160 21 0 37D 0110 52 063Totals 0 270 73 1.00AFind the following1) P(An D)=#) P(AU D) =I) P(D| A) =N) P(B| C) -

According to guidelines we solve first three subparts when we have given multiple subparts

Answered: Suppose events A, B, C, and D have…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question 1a) Suppose events A and B are independent, and events B and C are mutually exclusive.Their probabilities are P(A) = 0.4, P(B) = 0.5, and P(C) = 0.3. Findi) P(A ∩ B) ii) P(A ∪ B) iii) P(B ∪ C) iv) P(A|B) v) P(B|A)b) Let X be a random variable whose expectation and variance is known.If E[X] = 5, Var(X) = 4, then findi) E[(3 + 2X)^2] ii) Var[4 + 5X]
2a) ii) P(-1.54 Using calculator find the following probabilities: z≤1.75) O 0.5 0.4491 0.8982 0.1018 Jimmy and Rosalynn Carter celebrate 76 years of marriage toge
Use the attached image to compute the following probabilities:• P(B|A)• P(B ∩ A)• P(B0|A)• P(B0 ∩ A)
Step 4: Now calculate the probabilities P(AC) and P((A ∩ B)C) by first listing the simple events in AC and (A ∩ B)C. There are five simple events E1, E2, ..., E5. The complement of A is the collection of simple events that are not in A. We are given that A = {E2, E3}, so AC consists of the following event(s). (Select all that apply.) E1 E2 E3 E4 E5 We previously found that A ∩ B = {E2}. Therefore, the complement (A ∩ B)C includes the following event(s). (Select all that apply.) E1 E2 E3 E4 E5
1. Events A and B are mutually exclusive with P(A) = 0.280 and P(A or B) = 0.740 a) P(B)= b) P(Not A)= c) P(A and B)=
Which of the following values cannot be probabilities? 1, 1.49, 0.09, 3/5, 0, 5/3, - 0.45, /2 Select all the values that cannot be probabilities. O A. 1.49 O B. 0.09 O C. 5 3 O D. 1 O E. - 0.45 OF. V2 O G. 3 O H. 0
2. For the results of a certain survey, the estimated probability of being a binge drinker was 0.47 for males and 0.41 for females. Express each of these as a conditional probability. The probability of being a binge drinker (BD) was 0.47 for males (M). Express this as a conditional probability. A. P(BD|M) = 0.474 B. P(M|BD) 0.47 C. P(BD\M) = 0.53
3. From the tree diagram find the following probabilities 0.1 0.1 B 0.7 O.8 O. 1 0.4 B 0.5 (i) P(An E) (ii) P(A) (iii) P(A|E)
Construct a copy of figure 3.15 in your text, where the first outcome is one of A and B the second outcome in each case is one of a and b. Use the following probabilities instead of those given in your text:Pr[A]=2/7 Pr[B]=5/7Pr[a|A]=3/5Pr[b|A]=2/5Pr[a|B]=2/3Pr[b|B]=1/3 Find the following missing probabilities: Pr[B]= Pr[b]= Pr[b|B]= Pr[B|b]=
1. If P(A|B) = 0.5 and P(B) = 0.5, then the events A and B are independent. * true false
Q. 2 Two dice are thrown. The events A and B are taken to be Event A - "odd face on first die" Event B - "odd face on second die" Find the following probabilities: Р(А) Р(АВ) P(B) | P(B|A) Are events A and B statistically independent?
Q-3 If P(A) = 0.2, P(B) = 0.3, and P(A n B) = 0.1, determine the following probabilities: b. P(A U B) с. Р(А' n B) a. P(A' U B) d. P(A n B') e. P[(A U B)]

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Suppose events A, B, C, and D have probabilities as follows B Totals C 0 160 21 0.37 0.110 52 0 63 Totals 0 270 73 1.00 Find the following 1) P(AN D)= #) P(AU D)= H) P(D A)= N) P(B| C)-