Suppose an individual plays a gambling game where it is possible to lose $1.00 (it cost $1.00 to play the game), break even, win $3.00, or win $5.00 each time she plays. The probability distribution for each outcome is provided by the following table: $3.00 Outcome Probability -$1.00 0.30 S.00 $5.00 0.10 0.40 0.20 Two players are chosen at random. Let Xbe the winnings for Player 1, and Y the winnings for Player 2. Find the mean and standard deviation for their total winnings: X+Y.

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Suppose an individual plays a gambling game where it is possible to lose $1.00 (it cost $1.00 to play the
game), break even, win $3.00, or win $5.00 each time she plays. The probability distribution for each
outcome is provided by the following table:
Outcome
-$1.00
$0.00
$3.00
$5.00
Probability
0.30
0.40
0.20
0.10
Two players are chosen at random. Let X be the winnings for Player 1, and Y the winnings for Player 2.
Find the mean and standard deviation for their total winnings: X+ Y.
Transcribed Image Text:Suppose an individual plays a gambling game where it is possible to lose $1.00 (it cost $1.00 to play the game), break even, win $3.00, or win $5.00 each time she plays. The probability distribution for each outcome is provided by the following table: Outcome -$1.00 $0.00 $3.00 $5.00 Probability 0.30 0.40 0.20 0.10 Two players are chosen at random. Let X be the winnings for Player 1, and Y the winnings for Player 2. Find the mean and standard deviation for their total winnings: X+ Y.
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