Suppose an economy consists of three sectors: Energy (E), Manufacturing (M), and Agriculture (A). Sector E sells 70% of its output to M and 30% to A. Sector M sells 30% of its output to E, 50% to A, and retains the rest. Sector A sells 15% of its output to E, 30% to M, and retains the rest. Denote the prices (dollar values) of the total annual outputs of the Energy, Manufacturing, and Agriculture sectors by Pe. Pm, and pa respectively. If possible, find equilibrium prices that make each sector's income match its expenditures. Find the general solution as a vector, with på free. Pe Pa Pe Pm Pa Pm Pe Pm Pa [0.356 Pa 0.686 Pal Pa [0.465 Pa 0.593 Pa Pa [0.308 Pa 0716 Pa Pa [0607 Pa 0.481 Pa Pa

Advanced Engineering Mathematics
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Chapter2: Second-order Linear Odes
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Solve the problem.
Suppose an economy consists of three sectors: Energy (E), Manufacturing (M), and Agriculture (A).
Sector E sells 70% of its output to M and 30% to A.
Sector M sells 30% of its output to E, 50% to A, and retains the rest.
Sector A sells 15% of its output to E, 30% to M, and retains the rest.
Denote the prices (dollar values) of the total annual outputs of the Energy, Manufacturing, and Agriculture sectors by Pe. Pm, and Pa
respectively. If possible, find equilibrium prices that make each sector's income match its expenditures.
Find the general solution as a vector, with pa free.
0.356 Pal
Pm-0.686 Pa
Pe
Pa
Pe
Pm
Pa
Pe
Pm -
Pa
Pe
Pm
Pa
Pa
[0.465 Pa
= 0.593 Pa
Pa
[0.308 Pa
0.716 Pa
Pa
0.607 Pa
0.481 Pa
Pa
Transcribed Image Text:Solve the problem. Suppose an economy consists of three sectors: Energy (E), Manufacturing (M), and Agriculture (A). Sector E sells 70% of its output to M and 30% to A. Sector M sells 30% of its output to E, 50% to A, and retains the rest. Sector A sells 15% of its output to E, 30% to M, and retains the rest. Denote the prices (dollar values) of the total annual outputs of the Energy, Manufacturing, and Agriculture sectors by Pe. Pm, and Pa respectively. If possible, find equilibrium prices that make each sector's income match its expenditures. Find the general solution as a vector, with pa free. 0.356 Pal Pm-0.686 Pa Pe Pa Pe Pm Pa Pe Pm - Pa Pe Pm Pa Pa [0.465 Pa = 0.593 Pa Pa [0.308 Pa 0.716 Pa Pa 0.607 Pa 0.481 Pa Pa
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