Suppose Alice and Bob 8. Suppose Alice and Bob have the same RSA modulus n and suppose that their encryption exponents eд and eß are relatively prime.Charles wants to send the message x to Alice and Bob, so he encrypts to get yA = xºA (mod n) and YB = xв (mod n). Showhow Eve can find the plaintext x if she intercepts yA and yв.

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Answered: Suppose Alice and Bob have the same RSA…

Elements Of Modern Algebra

8th Edition

ISBN:9781285463230

Author:Gilbert, Linda, Jimmie

Publisher:Gilbert, Linda, Jimmie

Chapter2: The Integers

Section2.7: Introduction To Coding Theory (optional)

Problem 12E: Suppose that the check digit is computed as described in Example . Prove that transposition errors...

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Alice received the following ciphertext from Bob, "08 01 08 05". Bob had encrypted it using the RSA cypher with Alice's public key (pq, e) = (55, 3), where p = 5 and q = 11. Note that (p − 1)(q − 1) = 40. The value for d in Alice's private key, (pq, d) is a positive inverse for 3 modulo (p − 1)(q − 1). It was found to be 27 in Examples 8.4.8(b) and 8.4.10. What is Bob's message after Alice decrypts it? (Assume Bob encoded one letter at a time using the encoding A = 01, 8 = 02, C = 03, ..., Z = 26.) To decrypt Bob's message, Alice uses the decryption formula M = C mod where M is the code for a letter of the message, C is the encrypted version of the letter, (pq, e) = (55, 3) is the public key, and (pq, d) = (55, 27) is the private key. (a) To begin, Alice computes the values of a, b, c, d and e that are indicated below. 084 c (mod 55) 08¹ = a (mod 55) 088 d (mod 55) She finds that a = 082 b (mod 55) 0816e (mod 55) b = , C = d= and e = Because 27 = 16 + 8 + 2 + 1, 0827= 0816 +8+2+1 =…
Suppose (n, d) = (55, 3) is the private key of an RSA cryptosystem. If the received ciphertext is C = 49, what is the corresponding plaintext? 14 3 10 4
b) Suppose that the encryption function f(x) = (x-a) mod 26,0 ≤ x ≤ 25 and 0 ≤ a ≤ 25, encrypt the letter "F" by "A". Use the function f to decrypt the message "ZSVXO".
Suppose that the most common letter and the second most common letter in a long ciphertext produced by encrypting a plaintext using an affine cipher f (p) = (ap + b) mod 26 are Z and J, respectively. What are the most likely values of a and b?
Queston 2 only please
Suppose that you know that a ciphertext was produced by encrypting a plaintext message with a transposition cipher. How might you go about breaking it?
What is the decryption function for an affine cipher if the encryption function is c = (15p + 13) mod 26?
Decrypt the message "WFLRV" which is encrypted by the encryption function f (p) = (3p + 11) mod 26. a) VYACM b) ZASKW c) EHJLV d) CDVNZ
The system 2x + 3y = 4 (mod 4) 3x + 4y = 5 (mod 4) has no solution modulo 4. Select one: True False
Find all pairs of integers keys (a, b) for affine ciphers for which the encryption function c = (ap + b) mod 26 is the same as the corresponding decryption function.
i just need help with the last two question. im not sure on how to get the first number in the encryted message nor the last question
Calculate C(12,5) by hand. As C(n,r) = n!/(n-r)!r! identify n and r, and write out every number in n!, same with (n-r)! and r!. Then cancel numbers appropriately in the numerator and denominator and simplify to one number.

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