5. [11.1/16.7 Points] DETAILS MY NOTES EPPDISCMATH5 8.4.037. PREVIOUS ANSWERS ASK YOUR TEACHER PRACTICE ANOTHER Use the RSA cipher with public key (n, e) = (713, 43) to encrypt the word "SIS." Start by encoding the letters of the word "SIS" into their numeric equivalents. Assume the letters of the alphabet are encoded as follows: A = 01, B = 02, C = 03, Z = 26. Since the code for S is 19 and since e = 43 = 32 + 8 + 2 + 1, the first letter of the encrypted message is found by computing 19° 43 mod 713. 191a (mod 713) 192 b (mod 713) 194 c (mod 713) 198d (mod 713) 1916e (mod 713) 1932 = f (mod 713) The result is that a = 19 b = 361 , C = 555 d = 9 e=81 Thus, 1943 mod 713 = (a bd f) mod 713 = 570 . So the first number in the encrypted message is and f=144 Repeat these computations for each letter to find the complete encrypted message and enter your answer below. (Enter the message as a sequence of integer triples separated by a single space, where each triple is written using a fixed number of digits: 001 for 1, 002 for 2, 099 for 99.) Need Help? Read It Watch It
5. [11.1/16.7 Points] DETAILS MY NOTES EPPDISCMATH5 8.4.037. PREVIOUS ANSWERS ASK YOUR TEACHER PRACTICE ANOTHER Use the RSA cipher with public key (n, e) = (713, 43) to encrypt the word "SIS." Start by encoding the letters of the word "SIS" into their numeric equivalents. Assume the letters of the alphabet are encoded as follows: A = 01, B = 02, C = 03, Z = 26. Since the code for S is 19 and since e = 43 = 32 + 8 + 2 + 1, the first letter of the encrypted message is found by computing 19° 43 mod 713. 191a (mod 713) 192 b (mod 713) 194 c (mod 713) 198d (mod 713) 1916e (mod 713) 1932 = f (mod 713) The result is that a = 19 b = 361 , C = 555 d = 9 e=81 Thus, 1943 mod 713 = (a bd f) mod 713 = 570 . So the first number in the encrypted message is and f=144 Repeat these computations for each letter to find the complete encrypted message and enter your answer below. (Enter the message as a sequence of integer triples separated by a single space, where each triple is written using a fixed number of digits: 001 for 1, 002 for 2, 099 for 99.) Need Help? Read It Watch It
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
i just need help with the last two question. im not sure on how to get the first number in the encryted message nor the last question
![5. [11.1/16.7 Points]
DETAILS
MY NOTES
EPPDISCMATH5 8.4.037.
PREVIOUS ANSWERS
ASK YOUR TEACHER
PRACTICE ANOTHER
Use the RSA cipher with public key (n, e) = (713, 43) to encrypt the word "SIS." Start by encoding the letters of the word "SIS" into their numeric equivalents. Assume the letters of the alphabet are encoded as
follows: A =
01, B = 02, C = 03, Z = 26.
Since the code for S is 19 and since e = 43 = 32 + 8 + 2 + 1, the first letter of the encrypted message is found by computing 19°
43
mod 713.
191a (mod 713)
192 b (mod 713)
194 c (mod 713)
198d (mod 713)
1916e (mod 713)
1932 = f (mod 713)
The result is that a = 19
b = 361
, C = 555
d = 9
e=81
Thus, 1943
mod 713 = (a
bd f) mod 713 = 570
. So the first number in the encrypted message is
and f=144
Repeat these computations for each letter to find the complete encrypted message and enter your answer below. (Enter the message as a sequence of integer triples separated by a single space, where each triple
is written using a fixed number of digits: 001 for 1, 002 for 2, 099 for 99.)
Need Help?
Read It
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Transcribed Image Text:5. [11.1/16.7 Points]
DETAILS
MY NOTES
EPPDISCMATH5 8.4.037.
PREVIOUS ANSWERS
ASK YOUR TEACHER
PRACTICE ANOTHER
Use the RSA cipher with public key (n, e) = (713, 43) to encrypt the word "SIS." Start by encoding the letters of the word "SIS" into their numeric equivalents. Assume the letters of the alphabet are encoded as
follows: A =
01, B = 02, C = 03, Z = 26.
Since the code for S is 19 and since e = 43 = 32 + 8 + 2 + 1, the first letter of the encrypted message is found by computing 19°
43
mod 713.
191a (mod 713)
192 b (mod 713)
194 c (mod 713)
198d (mod 713)
1916e (mod 713)
1932 = f (mod 713)
The result is that a = 19
b = 361
, C = 555
d = 9
e=81
Thus, 1943
mod 713 = (a
bd f) mod 713 = 570
. So the first number in the encrypted message is
and f=144
Repeat these computations for each letter to find the complete encrypted message and enter your answer below. (Enter the message as a sequence of integer triples separated by a single space, where each triple
is written using a fixed number of digits: 001 for 1, 002 for 2, 099 for 99.)
Need Help?
Read It
Watch It
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