Suppose A + u are distinct eigenvalues of A, with corresponding eigenvectors u and v. (Au)™v = Au" v O pu"v V O du7v (Check ALL that apply) uv = are column vectors corresponding to the vectors u, v, then u'v is a Prove your result. Suggestion: If u, matrix whose entry is i · v.

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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
Section: Chapter Questions
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### Eigenvalues and Eigenvectors

In the following, type "u", "v", or "w" (without quotes) for **u**, **v**, **w**, and "kappa", "lambda", "mu", "nu" (without quotes) for the Greek letters κ, λ, μ, ν.

---

#### Example Problem:

Suppose **A** has eigenvalue λ corresponding to eigenvector **u**.

\[ \mathbf{A}(c\mathbf{u}) = \]

[Textbox]

An eigenvalue for **cA** is 

[Textbox]

, with corresponding eigenvector 

[Textbox].
Transcribed Image Text:### Eigenvalues and Eigenvectors In the following, type "u", "v", or "w" (without quotes) for **u**, **v**, **w**, and "kappa", "lambda", "mu", "nu" (without quotes) for the Greek letters κ, λ, μ, ν. --- #### Example Problem: Suppose **A** has eigenvalue λ corresponding to eigenvector **u**. \[ \mathbf{A}(c\mathbf{u}) = \] [Textbox] An eigenvalue for **cA** is [Textbox] , with corresponding eigenvector [Textbox].
### Eigenvalues and Eigenvectors Problem

Suppose \(\lambda \neq \mu\) are distinct eigenvalues of \(A\), with corresponding eigenvectors \(\mathbf{u}\) and \(\mathbf{v}\).

### Multiple Choice Question
\((A \mathbf{u})^T \mathbf{v} =\)

- \(\boxed{} \ A \mathbf{u}^T \mathbf{v}\)
- \(\boxed{} \ \mu \mathbf{u}^T \mathbf{v}\)
- \(\boxed{} \ \lambda \mathbf{u}^T \mathbf{v}\)

(Check ALL that apply)

### Short Answer Question
\[
\mathbf{u}^T \mathbf{v} = \boxed{\makebox[3em]{\text{}}}
\]

### Proof Prompt
Prove your result. Suggestion: If \(\mathbf{u}, \mathbf{v}\) are column vectors corresponding to the vectors \(\vec{u}, \vec{v}\), then \(\mathbf{u}^T \mathbf{v}\) is a matrix whose entry is \(\vec{u} \cdot \vec{v}\).

### Rich Text Editor 
(This is where you would type your proof)
```
Edit    Insert    Formats  ✓ B   I   U   X₂   X²      A   ▼  ◊
```

### Further Explanation
**Explain why a symmetric matrix with real entries can't have complex eigenvalues.**

Suggestion: If \(A\) is a matrix with real entries and \(\mathbf{v}\) is an eigenvector, then \(\mathbf{v}\) must also be an eigenvector. What is \(\mathbf{v}^T \mathbf{v}\)?

---
This text and hypothetical questions are designed to help students understand the properties of eigenvalues and eigenvectors, and encourage them to think critically about the behavior of different types of matrices.
Transcribed Image Text:### Eigenvalues and Eigenvectors Problem Suppose \(\lambda \neq \mu\) are distinct eigenvalues of \(A\), with corresponding eigenvectors \(\mathbf{u}\) and \(\mathbf{v}\). ### Multiple Choice Question \((A \mathbf{u})^T \mathbf{v} =\) - \(\boxed{} \ A \mathbf{u}^T \mathbf{v}\) - \(\boxed{} \ \mu \mathbf{u}^T \mathbf{v}\) - \(\boxed{} \ \lambda \mathbf{u}^T \mathbf{v}\) (Check ALL that apply) ### Short Answer Question \[ \mathbf{u}^T \mathbf{v} = \boxed{\makebox[3em]{\text{}}} \] ### Proof Prompt Prove your result. Suggestion: If \(\mathbf{u}, \mathbf{v}\) are column vectors corresponding to the vectors \(\vec{u}, \vec{v}\), then \(\mathbf{u}^T \mathbf{v}\) is a matrix whose entry is \(\vec{u} \cdot \vec{v}\). ### Rich Text Editor (This is where you would type your proof) ``` Edit Insert Formats ✓ B I U X₂ X² A ▼ ◊ ``` ### Further Explanation **Explain why a symmetric matrix with real entries can't have complex eigenvalues.** Suggestion: If \(A\) is a matrix with real entries and \(\mathbf{v}\) is an eigenvector, then \(\mathbf{v}\) must also be an eigenvector. What is \(\mathbf{v}^T \mathbf{v}\)? --- This text and hypothetical questions are designed to help students understand the properties of eigenvalues and eigenvectors, and encourage them to think critically about the behavior of different types of matrices.
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