Suppose a survey of a random sample of 100 smokers, conducted by the Department of Health, suggests that the mean number of cigarettes a person smokes in a day in Smokelandia (Y) is 2.72 and the standard deviation (sy) is 0.58. The Department of Health is concerned about theresults of the survey and wants to test whether the mean number of cigarettes a person smokes in a day is 2.51 or not.The test statistic associated with the above test is 3.6204(Round your answer to two decimal places.)If the Department of Health uses a 5% significance level, the test statistic suggests that wethe hypothesis that the mean number of cigarettes a person smokes in a day is 2.51.Suppose the Department of Health decides to reject the null hypothesis (H,) if |Y- 2.51|>0.08.The size of the above test is(Round your answer to two decimal places.)If u = 2.69, the power of the above test is(Round your answer to two decimal places.)

Answered: Image /qna-images/answer/d057fb70-2b82-4bb9-bafc-3af7abd53326.jpg

Answered: Suppose a survey of a random sample of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In a certain country the heights of adult men are normally distributed with a mean of 68.8 inches and a standard deviation of 2.4 inches. The country's military requires that men have heights between 65 inches and 77 inches. Determine what percentage of this country's men are eligible for the military based on height.
A college placement office conducted a survey of 100 engineers who had graduated from Stanford University. For these engineers, the mean salary was computed to be $72,000 with a standard deviation of $8,000. What percentage of these engineers earn more than $96.000 or less than $48,000. Use the chebysheff's theorem!!
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2. Does helping another person affect the helper's life satisfaction? To find out, a researcher randomly sampled 64 people and asked each of them to help one other person that day. At the end of the day, each participant completed a standardized measure of life satisfaction. The mean score for the sample was 51.60. In the general population, the mean score on this measure is 50 and the standard deviation is 6. Test the hypothesis that helping affects life satisfaction (a = .05, two-tailed). You don't have to outline all 5 steps of hypothesis testing, but specify the properties of the comparison distribution, the critical value of the test statistic for rejecting the null hypothesis, the obtained test statistic, and the final decision. What are the lower and upper confidence limits for the 95% confidence interval of the mean life satisfaction of people who have helped someone else that day? Compute the standardized effect size.
Suppose that the daily intake of an adult follows a uniform distribution from 40 to 65 micrograms. Suppose that 36 adults are randomly selected. What is the mean and standard deviation of the average intake for 36 adults. a. Mean= 52.5 stvdev = 1.2 b. Mean = 55 stvdev= 7.22c. Mean = 52.5 stvdev = 2.08 d. Mean= 52.5 stvdev = 7.22
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