5.8 3.3 2.8 95.6 5.0 3.4Suppose a study reported that the average person watched 5.51 hours of television per day. A random sample of 15 people gave the number of hours of television watched per day shown. At the 1%significance level, do the data provide sufficient evidence to conclude that the amount of television watched per day last year by the average person differed from the value reported in the study? (Note:x= 4.287 hours and s= 1.244 hours.)3.2 5.7 2.94.3 6.2 5.73.5 3.9 3.0Click here to view a partial table of values of tSet up the hypotheses for the one-mean t-test.Ho PHa PThe test statistic is t=(Round to two decimal places as needed.)The P-value is(Round to four decimal places as needed.)the value reported in the study.sufficient evidence to conclude that the amount of television watched by the average person isthe null hypothesis. The data

Answered: Image /qna-images/answer/51ccc2e1-4a88-4ceb-b148-4e11da3928e2.jpg

Answered: Suppose a study reported that the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose IQ scores were obtained for 20 randomly selected sets of siblings. The 20 pairs of measurements yield x = 101.13, y = 103.5, r=0.867, P-value = 0.000, and y = 6.25 +0.96x, where x represents the IQ score of the younger child. Find the best predicted value of y given that the younger child has an IQ of 101? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of ŷ is. (Round to two decimal places as needed.)
The mean BMI in patients free of diabetes was reported as 28.2. An investigator conduction the study hypothesizes that the BMI in patients free of diabetes is higher. Based on the data, is there evidence that the BMI is sigificantly higher than 28.2? Use a 5% level of significance. 25 . 27 . 31 . 33 . 26 . 28 . 41 . 24 . 32 . 35 . 40 .
Suppose a study reported that the average persin watched 3.37 hours of television per day. a random sample of 15 people gave the number of hours of television watched per day shown below. at the 1% significance level, do the data provide sufficent evidence to conclude that the amount of television watched per day last year by the average person is greater than the value reported in the study? what is the test statistic value for this problem? a.0.28 b.-38 c.none of the above d. 0.58 e.-4.295 f..04 g. 1.94 . the proper conclusion for this problem is? a. reject the null hypothesis we have sufficent evidence to prove the average number of hours people watch tv is more than 3.37 hours. b. Do not reject the null hypothesis we have sufficient evidence to prove the average number of hours of TV watched is greater than 3.37 hours c. Reject the null hypothesis and claim the average number of hours people watch TV is less than 3.37 because the P value is near zero d. Do not reject the null…
A dietician wishes to see if a person’s cholesterol level will change if the diet is supplemented by a certain mineral. Six randomly selected subjects were pretested, and then they took the mineral supplement of a 6 week period. The results are shown in the table below. Can it be concluded that the cholesterol level has changed at a significance level of 0.10? Use the P-value method with your calculator. Assume the variable is approximately normally distributed. You can use your calculator to answer this question but make sure that you clearly write the statements for the null and alternative hypothesis. Be sure that you thoroughly explain your final conclusion using the P-value method. Subject 1 2 3 4 5 6 Before 210 235 208 190 172 244 After 190 170 210 188 173 228
Consider a sample data with x=25 and s=2. Compute a chebyshev’s interval for which at least 89% of the data will lie?
According to a recent article about individuals who have credit cards, the mean number of cards per person with credit cards is 4.5. To test this result a random survey of 60 individuals who have credit cards was conducted. The survey only includes the number of credit cards per participant. The results of the survey are attached below. (a) What is the variable of interest in this study? Is it qualitative or quantitative? (b) Do the results of the survey imply that the mean number of cards per individual is less than 4.5? Use the a = 0.05 level of significance. E Click the icon to view the data from the survey. (a) What is the variable of interest in this study? Is it qualitative or quantitative? The variable of interest is number of credit cards.It is a quantitative variable. (b) Do the results of the survey imply that the mean number of cards per individual is less than 4.5? Use the a = 0.05 level of significance. State the null and alternative hypotheses. Họ: H = 4.5 < 4.5 H1: H…
A hypertension trial is mounted, and 12 participants are randomly assigned to receive either a new medication or a placebo. Each participant takes the assigned medication, and the participants’ SBP is recorded after 6 months on the assigned medication. The data are shown in Table 7–9. Is there a difference in mean SBP between treatments? Run the appropriate test at a = 0.05. Placebo New Medication 134 114 143 117 148 121 142 124 150 122 160 128
Each person in random samples of 227 male and 293 female working adults living in a certain town in Canada was asked how long, in minutes, his or her typical daily commute was. Is there enough evidence to show that there is a difference in mean commute times for male and female working residents of this town? (Use males females) Male Female Sample size X S Sample size x S 227 30.2 24.0 293 27.9 24.3 Find the test statistic. (Round your answer to two decimal places.) Find the df. (Round your answer down to the nearest whole number.) df= Use technology to find the P-value. (Round your answer to four decimal places.) P-value= Is there enough evidence to show that there is a difference in mean commute times for male and female working residents of this town? Use a significance level of 0.05. Yes No
Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x= 100.1, y = 98.3, r=0.961, P-value = 0.000, and y = - 18.02 + 1.16x, where x represents the IQ score of the wife. Find the best predicted value of y given that the wife has an IQ of 100? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is (Round to two decimal places as needed.)
Suppose IQ scores were obtained for 20 randomly selected sets of siblings. The 20 pairs of measurements yield x = 102.13, y = 101.35, r= 0.927, P-value = 0.000, and y = 2.05 + 0.97x, where x represents the IQ score of the older child. Find the best predicted value of y given that the older child has an IQ of 103? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. Critical Values of the Pearson Correlation Coefficient r The best predicted value of y is (Round to two decimal places as needed.) Critical Values of the Pearson Correlation Coefficient r a = 0.05 a = 0.01 NOTE: To test Ho: p=0 Jagainst H,: p#0, reject H, lif the absolute value of r is greater than the critical value in the table. 4. 0.950 0.990 0.878 0.959 6 0.811 0.917 0.754 0.875 8. 0.707 0.834 0.666 0.632 0.602 9 0.798 10 0.765 11 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 0.468 0.456 18 0.590 19 0.575…
To examine the linear correlation between adult age and weight, data was collected from 8 adults. See the table below. Age Weight (Years) (pounds) 35 223 38 231 48 121 50 148 52 219 55 210 56 132 57 218 Does this result suggest that the correlation is statistically significant? Use a = 0.10. Important Note: Round your value for r to three decimals before computing the STS. DO NOT use the built- in LinRegTTest on a calculator because you might get marked wrong. When computing the P-value, use the rounded STS. 1. Select the correct statement: O Even if the correlation is found to be statistically significant, that does not necessarily mean that changes in x cause changes in y O If the correlation is found to be statistically significant, that means that changes in x cause changes in y The hypotheses are: O Ho:r = 0; Ha:r#0 O Ho:r 0 O Ho:p = 0; Ha:p+ 0 O Ho:p 2 0; Ha:p 0 O Ho:r > 0; Ha:r <0 MacBook Air 20 F3 000 11 F8 F4 F5 F6 F7 F9
13.34 Women's heights. The heights of adult women are approximately Normal with mean 69.2 inches and standard deviation 2.5 inches. How tall are the tallest 10% of women? (Use the closest percentile that appears in Table B.)

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