Suppose a simple random sample of size n= 200 is obtained from a population whose size is N= 20,000 and whose population proportion with a specified characteristic p=0.4. Complete parts (a) through (C) below. O D. ApprOXimately rorImai Decause nsU.UDIV aru rpu- P)210. O C. Not normal because ns0.05N and np(1 - p) 2 10. O D. Approximately normal because ns0.05N and np(1 - p) < 10. Determine the mean of the sampling distribution of p. HA= 0.4 (Round to one decimal place as needed.) Determine the standard deviation of the sampling distribution of p GA = 0.034641 (Round to six decimal places as needed) (b) What is the probability of obtaining x = 90 or more individuals with the characteristic? That is, what is P(p20.45)7 PÔ20.45) = 0.0745 (Round to four decimal places as needed) (c) What is the probability of obtaining x = 66 or fewer individuals with the characteristic? That is, what is P(ps0.33)? Pos0.33) = (Round to four decimal places as needed.)

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Suppose a simple random sample of size \( n = 200 \) is obtained from a population whose size is \( N = 20,000 \) and whose population proportion with a specified characteristic is \( p = 0.4 \). Complete parts (a) through (c) below.

**Options:**
- A. Approximately normal because \( n \leq 0.05N \) and \( np(1 - p) \geq 10 \).
- B. Not normal because \( n > 0.05N \) and \( np(1 - p) \geq 10 \).
- C. Not normal because \( n \leq 0.05N \) and \( np(1 - p) < 10 \).
- D. Approximately normal because \( n > 0.05N \) and \( np(1 - p) \geq 10 \).

**Determine the mean of the sampling distribution of \( \hat{p} \):**
\[
\mu_{\hat{p}} = p = 0.4 \quad \text{(Round to one decimal place as needed.)}
\]

**Determine the standard deviation of the sampling distribution of \( \hat{p} \):**
\[
\sigma_{\hat{p}} = 0.034641 \quad \text{(Round to six decimal places as needed.)}
\]

**(b) What is the probability of obtaining \( x = 90 \) or more individuals with the characteristic? That is, what is \( P(\hat{p} \geq 0.45) \)?**
\[
P(\hat{p} \geq 0.45) = 0.0745 \quad \text{(Round to four decimal places as needed.)}
\]

**(c) What is the probability of obtaining \( x = 66 \) or fewer individuals with the characteristic? That is, what is \( P(\hat{p} \leq 0.33) \)?**
\[
P(\hat{p} \leq 0.33) = 0.0918 \quad \text{(Round to four decimal places as needed.)}
\]
Transcribed Image Text:Suppose a simple random sample of size \( n = 200 \) is obtained from a population whose size is \( N = 20,000 \) and whose population proportion with a specified characteristic is \( p = 0.4 \). Complete parts (a) through (c) below. **Options:** - A. Approximately normal because \( n \leq 0.05N \) and \( np(1 - p) \geq 10 \). - B. Not normal because \( n > 0.05N \) and \( np(1 - p) \geq 10 \). - C. Not normal because \( n \leq 0.05N \) and \( np(1 - p) < 10 \). - D. Approximately normal because \( n > 0.05N \) and \( np(1 - p) \geq 10 \). **Determine the mean of the sampling distribution of \( \hat{p} \):** \[ \mu_{\hat{p}} = p = 0.4 \quad \text{(Round to one decimal place as needed.)} \] **Determine the standard deviation of the sampling distribution of \( \hat{p} \):** \[ \sigma_{\hat{p}} = 0.034641 \quad \text{(Round to six decimal places as needed.)} \] **(b) What is the probability of obtaining \( x = 90 \) or more individuals with the characteristic? That is, what is \( P(\hat{p} \geq 0.45) \)?** \[ P(\hat{p} \geq 0.45) = 0.0745 \quad \text{(Round to four decimal places as needed.)} \] **(c) What is the probability of obtaining \( x = 66 \) or fewer individuals with the characteristic? That is, what is \( P(\hat{p} \leq 0.33) \)?** \[ P(\hat{p} \leq 0.33) = 0.0918 \quad \text{(Round to four decimal places as needed.)} \]
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