a) What is the sample size, found at the bottom of the table? 2072 b) What is the point estimate for the top row, "Attempted and completed", under "% Ever"? 51.3% (The numbers in the table are percentages. Either add a % to your answer or convert to a decimal.) P(1 – p) c) The standard error can be computed using the formula SE = , where p is the point n estimate and n is the sample size. What is the standard error for part B?
a) What is the sample size, found at the bottom of the table? 2072 b) What is the point estimate for the top row, "Attempted and completed", under "% Ever"? 51.3% (The numbers in the table are percentages. Either add a % to your answer or convert to a decimal.) P(1 – p) c) The standard error can be computed using the formula SE = , where p is the point n estimate and n is the sample size. What is the standard error for part B?
MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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Transcribed Image Text:a) What is the sample size, found at the bottom of the table? 2072
b) What is the point estimate for the top row, "Attempted and completed", under "% Ever"?
51.3%
v (The numbers in the table are percentages. Either add a % to your answer or convert to a
decimal.)
P(1 – p)
c) The standard error can be computed using the formula SE =
where p is the point
n
estimate and n is the sample size. What is the standard error for part B?
d) Use your answers for Parts B and C to compute the 95% confidence interval for the proportion of
children who have ever been victimized (attempted or completed):
We are 95% confident that the true proportion of children who had been vicitmized (attempted or
completed) is between
and
. (Enter the smaller number first.
Answers can be written as a decimal, like 0.752, or as a percent, like 75.2%.)
e) The table gives the 95% confidence interval at (49.1 – 53.5). Does your confidence interval from Part
D match with the table? ?
Expert Solution

Step 1:-
Here it is given that,
Sample size n= 2072
And point estimate, p^= 51.3% = 0.513
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