Suppose a random sample of 100 observations from a binomial population gives a value of p=0.54 and you wish to test the null hypothesis that the population parameter p is equal to 0.50 against the alternative hypothesis that p is greater than 0.50. Complete parts a through c. a. Noting that p=0.54, what does your intuition tell you? Does the value of p appear to contradict the null hypothesis? OA. Yes, because p satisfies H₂: p>0.50 and is not very close to 0.50. OB. Yes, because p satisfies H₂: p>0.50 and is very close to 0.50. OC. Yes, because p is very close to 0.50. OD. No, because p is very close to 0.50. b. Use the large-sample z-test to test Ho: p=0.50 against the alternative hypothesis, Ha: p>0.50. Use α = 0.10. If a = 0.10, find the rejection region for the test. Choose the correct answer below. OA. z<-1.645 OC. z< -1.28 or z> 1.28 OE. z> 1.28 Calculate the value of the test statistic. Z= (Round to two decimal places as needed.) What is the conclusion of the test? OA. Do not reject the null hypothesis because the test statistic is not in the rejection region. OB. Reject the null hypothesis because the test statistic is not in the rejection region. OC. Reject the null hypothesis because the test statistic is in the rejection region. OB. z<-1.645 or z> 1.645 OD. z> 1.645 OF. z< -1.28
Suppose a random sample of 100 observations from a binomial population gives a value of p=0.54 and you wish to test the null hypothesis that the population parameter p is equal to 0.50 against the alternative hypothesis that p is greater than 0.50. Complete parts a through c. a. Noting that p=0.54, what does your intuition tell you? Does the value of p appear to contradict the null hypothesis? OA. Yes, because p satisfies H₂: p>0.50 and is not very close to 0.50. OB. Yes, because p satisfies H₂: p>0.50 and is very close to 0.50. OC. Yes, because p is very close to 0.50. OD. No, because p is very close to 0.50. b. Use the large-sample z-test to test Ho: p=0.50 against the alternative hypothesis, Ha: p>0.50. Use α = 0.10. If a = 0.10, find the rejection region for the test. Choose the correct answer below. OA. z<-1.645 OC. z< -1.28 or z> 1.28 OE. z> 1.28 Calculate the value of the test statistic. Z= (Round to two decimal places as needed.) What is the conclusion of the test? OA. Do not reject the null hypothesis because the test statistic is not in the rejection region. OB. Reject the null hypothesis because the test statistic is not in the rejection region. OC. Reject the null hypothesis because the test statistic is in the rejection region. OB. z<-1.645 or z> 1.645 OD. z> 1.645 OF. z< -1.28
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Suppose a random sample of 100 observations from a binomial population gives a value of p=0.54 and you wish to test the null hypothesis that the population parameter p is equal to 0.50 against
the alternative hypothesis that p is greater than 0.50. Complete parts a through c.
a. Noting that p=0.54, what does your intuition tell you? Does the value of p appear to contradict the null hypothesis?
OA. Yes, because p satisfies H₂: p>0.50 and is not very close to 0.50.
OB. Yes, because p satisfies H₂: p>0.50 and is very close to 0.50.
OC. Yes, because p is very close to 0.50.
O D. No, because p is very close to 0.50.
b. Use the large-sample z-test to test Ho: p=0.50 against the alternative hypothesis, Ha: p>0.50. Use α=0.10.
If α = 0.10, find the rejection region for the test. Choose the correct answer below.
OA. z< -1.645
OC. z< -1.28 or z> 1.28
OE. Z> 1.28
Calculate the value of the test statistic.
Z= (Round to two decimal places as needed.)
What is the conclusion of the test?
O A. Do not reject the null hypothesis because the test statistic is not in the rejection region.
OB. Reject the null hypothesis because the test statistic is not in the rejection region.
OC. Reject the null hypothesis because the test statistic is in the rejection region.
OB. z<-1.645 or z> 1.645
O D. z> 1.645
OF. z< -1.28
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