Suppose a population has a mean weight of μ = 79.676 kg and a standard deviation of σ=22.4943. For samples of size n= 36, A sample of size n=36 is taken. Approximate the probability of observing a sample mean of less than 71.5 kg. (hint: use number 1). In calculating the z-score, round your z-score to two decimal places. Use the normal table to find the probability and give answer to 4 decimal places. Suppose a population has a mean weight of μ = 79.676 kg and a standard deviation of σ=22.4943. For samples of size n= 36, A sample of size n=36 is taken. Approximate the probability of observing a sample mean of between71.5 kg and 85 kg. (hint: use numbers 2 and 4). In calculating the z-score, round your z-score to two decimal places. Use the normal table to find the probability and give answer to 4 decimal places. Suppose a population has a mean weight of μ = 79.676 kg and a standard deviation of σ=22.4943. For samples of size n= 36, A sample of size n=36 is taken. Approximate the weight that lies at the 95th percentile of the sampling distribution. (hint: use number 1, the equation and the fact that the 95th percentile of the standard normal distribution is approximately z = 1.645). Round your estimated 95th percentile average weight to two decimal places.
Suppose a population has a mean weight of μ = 79.676 kg and a standard deviation of σ=22.4943. For
Suppose a population has a mean weight of μ = 79.676 kg and a standard deviation of σ=22.4943. For samples of size n= 36, A sample of size n=36 is taken. Approximate the probability of observing a sample mean of between71.5 kg and 85 kg. (hint: use numbers 2 and 4). In calculating the z-score, round your z-score to two decimal places. Use the normal table to find the probability and give answer to 4 decimal places.
Suppose a population has a mean weight of μ = 79.676 kg and a standard deviation of σ=22.4943. For samples of size n= 36, A sample of size n=36 is taken. Approximate the weight that lies at the 95th percentile of the sampling distribution. (hint: use number 1, the equation and the fact that the 95th percentile of the standard
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