Suppose a geneticist uses a three-point testcross to map three recessive, linked hummingbird wing-shape mutations called tk, f, and s, where tk is associated with thick wings, f is associated with flat wings, and s is associated with sharp wings. He first crosses homozygous sharp birds to homozygous thick, flat birds. Next, he testcrosses the Fi progeny to thick, flat, sharp birds. He obtained the results shown. Given this data, label the progeny phenotypic classes as either parental, single crossover (SCO), or double crossover (DCO) recombinant types. Each label may be used multiple times. Two classes have already been filled in. Phenotype Number Recombinant type sharp 819 Answer Bank thick, flat 821 SCO DCO flat 183 parental thick, sharp 169 SCO thick 6. flat, sharp thick, flat, sharp 28 SCO wild type 26

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Question 10 of 18
Attempt 10
Suppose a geneticist uses a three-point testeross to map three recessive, linked hummingbird wing-shape mutations called
tk, f, and s, where tk is associated with thick wings, f is associated with flat wings, and s is associated with sharp wings.
He first crosses homozygous sharp birds to homozygous thick, flat birds. Next, he testcrosses the Fi progeny to thick, flat,
sharp birds. He obtained the results shown.
Given this data, label the progeny phenotypic classes as either parental, single crossover (SCO), or double crossover
(DCO) recombinant types. Each label may be used multiple times. Two classes have already been filled in.
Phenotype
Number
Recombinant type
sharp
819
Answer Bank
thick, flat
821
SCO
DCO
flat
183
parental
thick, sharp
169
SCO
thick
6.
flat, sharp
thick, flat, sharp
28
SCO
wild type
26
Transcribed Image Text:Question 10 of 18 Attempt 10 Suppose a geneticist uses a three-point testeross to map three recessive, linked hummingbird wing-shape mutations called tk, f, and s, where tk is associated with thick wings, f is associated with flat wings, and s is associated with sharp wings. He first crosses homozygous sharp birds to homozygous thick, flat birds. Next, he testcrosses the Fi progeny to thick, flat, sharp birds. He obtained the results shown. Given this data, label the progeny phenotypic classes as either parental, single crossover (SCO), or double crossover (DCO) recombinant types. Each label may be used multiple times. Two classes have already been filled in. Phenotype Number Recombinant type sharp 819 Answer Bank thick, flat 821 SCO DCO flat 183 parental thick, sharp 169 SCO thick 6. flat, sharp thick, flat, sharp 28 SCO wild type 26
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