Suppose A E C such that A(2 + i, 3 – i) = (5 – i,7 – 5i). Then (1) A = (1 – i) (2) A = (2 – i)

Algebra and Trigonometry (6th Edition)
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ISBN:9780134463216
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Suppose A E C such that A(2+ i,3 – i) = (5 – i, 7 – 5i). Then
(1) A = (1 – i)
(2) A = (2 – i)
(3) Does not exist A
(4) None of the given answers is true
OA. Option (1) is true
OB. Option (2) is true
C. None of the given answers is true
OD. Option (3) is true
1.
For a, b e R, let S be a subset of R? defined as S = {(x, y) E R³ : r + 2y – ax²y² = b} .
Then S is a subspace of R? if
OA. a = b =1
OB. a = 1, 6 = 0
OC. a = 0, 6 = 1
OD. None of the given answers is true
2.
all
04:00 PM
2021-10-25
Page: 1 of 1
Words: 2
E EI E E 96% e
Transcribed Image Text:Document2 - Microsoft Word (Product Activation Failed) File Home Insert Page Layout References Mailings Review View a ? W % Cut 三 幸 外 T A Find Aal Calibri (Body) - 11 * A A Aa AaBbCcDc AaBbCcDc AaBbC AaBbCc AaBI AaBbCcL E Copy Сopy ae Replace Paste BI U в IUabe X, х* ab A I Normal I No Spaci. Heading 1 Change . Heading 2 Title Subtitle - Format Painter Styles - Select - Clipboard Font Paragraph Styles Editing 2:1·1•: :M1A: 2:1·3•1: 4:1:5•1 : 6.1:7:1 8. 19.1· 10. 1 11: I · 12. 1 13. I14: 1 15. I • 3.1: 4. L:5.16L:7:1:8:9.1 10. 11:1 12.1 13.1 14. 15.1 7.1 '18. L Suppose A E C such that A(2+ i,3 – i) = (5 – i, 7 – 5i). Then (1) A = (1 – i) (2) A = (2 – i) (3) Does not exist A (4) None of the given answers is true OA. Option (1) is true OB. Option (2) is true C. None of the given answers is true OD. Option (3) is true 1. For a, b e R, let S be a subset of R? defined as S = {(x, y) E R³ : r + 2y – ax²y² = b} . Then S is a subspace of R? if OA. a = b =1 OB. a = 1, 6 = 0 OC. a = 0, 6 = 1 OD. None of the given answers is true 2. all 04:00 PM 2021-10-25 Page: 1 of 1 Words: 2 E EI E E 96% e
Expert Solution
Step 1

Given that: 1. λC, λ(2+i, 3-i)=(5-i, 7-5i)

 

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