Suppose a duck lives in a universe in which h=2πJ⋅s h=2πJ⋅s. The duck has a mass of 2.00 kg and is initially known to be within a pond 1.00 m wide. (a) What is the minimum uncertainty in the component of the duck’s velocity parallel to the pond’s width? (b) Assuming this uncertainty in speed prevails for 5.00 s, determine the uncertainty in the duck’s position after this time interval.
Suppose a duck lives in a universe in which h=2πJ⋅s h=2πJ⋅s. The duck has a mass of 2.00 kg and is initially known to be within a pond 1.00 m wide. (a) What is the minimum uncertainty in the component of the duck’s velocity parallel to the pond’s width? (b) Assuming this uncertainty in speed prevails for 5.00 s, determine the uncertainty in the duck’s position after this time interval.
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Suppose a duck lives in a universe in which h=2πJ⋅s
h=2πJ⋅s. The duck has a mass of 2.00 kg and is initially known to be within a pond 1.00 m wide. (a) What is the minimum uncertainty in the component of the duck’s velocity parallel to the pond’s width? (b) Assuming this uncertainty in speed prevails for 5.00 s, determine the uncertainty in the duck’s position after this time interval.
![a) The uncertainty principle is given as:
h
ApAr >
4T
The minimum uncertainty of the velocity is obtained for the maximum
uncertainty of the position. Therefore:
Ar = 1 m
Thus:
h
mAuAr =
47
h
Δu=
4TArm
2т.Js
> Au =
4т 1m -2 kg
> Au =|0.25 ms'
b) If this uncertainty of velocity prevails for five seconds, we can simply
imagine that our position uncertainty grows for:
Az' =
= Aut
=|1.25 m
Therefore our final uncertainty of position is:
AX = Ar+ Ar
> AX =2.25 m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F66b10451-602f-4902-8ddc-2b05436f7c36%2F659ba104-2157-4d00-b260-1527ab64cb5c%2Faqfy1j_processed.png&w=3840&q=75)
Transcribed Image Text:a) The uncertainty principle is given as:
h
ApAr >
4T
The minimum uncertainty of the velocity is obtained for the maximum
uncertainty of the position. Therefore:
Ar = 1 m
Thus:
h
mAuAr =
47
h
Δu=
4TArm
2т.Js
> Au =
4т 1m -2 kg
> Au =|0.25 ms'
b) If this uncertainty of velocity prevails for five seconds, we can simply
imagine that our position uncertainty grows for:
Az' =
= Aut
=|1.25 m
Therefore our final uncertainty of position is:
AX = Ar+ Ar
> AX =2.25 m
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