Suppose a dresser drawer has blue shirts, yellow shirts, red shirts, and green shirts so that if a shirt is pulled from the drawer at random, each color has an equal chance of being drawn. P(Green) = P(Blue) = P(Red) = P(Yellow) = ¼. Complete parts (a) – (d) to create a probability distribution for the number of yellow shirts if two shirts are pulled from the drawer at random (replacing the

College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter8: Sequences, Series,and Probability
Section8.7: Probability
Problem 6ECP: In Pennsylvania’s Cash 5 game, a player chooses five different numbers from 1 to 43. If these five...
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Suppose a dresser drawer has blue shirts, yellow shirts, red shirts, and green shirts so that if a shirt is pulled from the drawer at random, each color has an equal chance of being drawn. P(Green) = P(Blue) = P(Red) = P(Yellow) = ¼. Complete parts (a) – (d) to create a probability distribution for the number of yellow shirts if two shirts are pulled from the drawer at random (replacing the shirt after each draw).

*  Make a table that displays each event from (b)

Green, Yellow / Blue, Yellow / Red, Yellow

Yellow, Yellow

* and the corresponding probability from (a).

Green, Blue, / Green, Red,  / Green, Yellow, /  Green, Green

Blue, Green / Blue, Blue / Blue, Red / Blue, Yellow

Red, Green / Red, Blue / Red, Red / Red, Yellow

Yellow, Green / Yellow, Blue / Yellow, Red / Yellow, Yellow

This is a probability distribution for the number of yellow shirts drawn when two shirts are randomly pulled from the drawer.

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